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erik [133]
3 years ago
11

Which quantity is larger? A) 100500 B) 1000300 C) They are equal. D) Insufficient information.

Mathematics
1 answer:
lapo4ka [179]3 years ago
8 0
Quantity is two numbers multiplied together, judging by the context, the answer is D, insufficient information.

Choice a and b are just numbers.
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Write (7,3) and (4,0) in slope intercept form
bazaltina [42]
The answer is y=x-4
7 0
3 years ago
Two time the sum of x plus 3 is 6 more than than two times x
IgorLugansk [536]

Answer:

2(x+3)=2x+6

2x+6=2x+6

Step-by-step explanation:

2(x+3)=2x+6

2x+6=2x+6

5 0
3 years ago
50/24= x/495<br> what does x =
vesna_86 [32]

Answer:

1031.25 =x

Step-by-step explanation:

50/24 = x /495

We can use cross products to solve

50 *495 = 24*x

24750 = 24x

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7 0
3 years ago
Read 2 more answers
there are nickels, dimes, and quarters in a piggy bank. altogether, the coins are worth $3.65. the number of dimes is three time
hoa [83]

This question is solved using a system of equations, and doing this, we get that: There are 9 quarters, 4 nickels and 12 dimes.

I am going to say that:

x is the number of nickels.

y is the number of dimes.

z is the number of quarters.

In all, they are worth $3.65.

A nickel is worth $0.05, a dime is worth $0.1 and a quarter is worth $0.25, so:

0.05x + 0.1y + 0.25z = 3.65

Dimes: 3 times greater than nickels:

This means that:

y = 3x

Quarters: One greater than double the number of nickels:

This means that:

z = 2x + 1

Value of x:

We have y and z as function of x, so we can replace into the equation and find the value of x, so:

0.05x + 0.1y + 0.25z = 3.65

0.05x + 0.1(3x) + 0.25(2x+1) = 3.65

0.05x + 0.3x + 0.5x + 0.25 = 3.65

0.85x = 3.4

x = \frac{3.4}{0.85}

x = 4

y and z:

y = 3x = 3(4) = 12

z = 2x + 1 = 2(4) + 1 = 9

There are 9 quarters, 4 nickels and 12 dimes.

A similar question is found at brainly.com/question/17096268

4 0
3 years ago
Find center and radius<br> (x-3)^2+y^2=8
Flauer [41]

Answer:

<h2>Center: (3, 0)</h2><h2>Radius: 2√2</h2>

Step-by-step explanation:

The equation of a circle in standard form:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the equation:

(x-3)^2+y^2=8\to(x-3)^2+(y-0)^2=(\sqrt8)^2

Therefore

the center: (3,\ 0)

the radius: r=\sqrt8\to r=\sqrt{4\cdot2}\to r=\sqrt4\cdot\sqrt2\to r=2\sqrt2

4 0
3 years ago
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