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olasank [31]
3 years ago
9

Find the x-intercept for the line represented by this equation.

Mathematics
1 answer:
k0ka [10]3 years ago
3 0
3(0) = 2x + 6
( 0 = 2x + 6 ) - 6
( -6 = 2x ) /2
x = -3
The answer is B. (-3, 0).
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YO please help actually been waiting for an hour and a half cuz so many trolls lol. <3 giivng brainliest, and ty in advance g
kati45 [8]

Hello!

For this problem we are given that quadrilateral ABCD is congruent to quadrilateral GJIH, meaning that all sides and angle measures will be equivalent to its corresponding side.

This means that to find x, we can look at quadrilateral GJIH's corresponding side to quadrilateral ABCD's side AD, which is side GH, which has a value of 9.

This means that 9 should also be the side length of side AD, which we're given a value of x/3.

x/3=9

Solve.

x=27

Hope this helps!

8 0
2 years ago
Read 2 more answers
Subtact: (9x + 5) - (4x + 3)​
jek_recluse [69]

Answer:

5x+2

Step-by-step explanation:

(9x+5)-(4x+3)

5x+2

8 0
2 years ago
the art club receives $10 plus $2 for every sculpture they sell for a fundraiser. the expression 2x+10 represents the amount the
Len [333]
2x + 10...the common number between these 2 terms is 2...so factor the 2 out

2(x + 5) <==
8 0
3 years ago
A new cell phone cost $85, and the sales tax is 9%. What is the amount of the sales tax
elixir [45]

The sales tax is $7.67

In total, with the sales tax, the phone would be $92.65

4 0
3 years ago
Do you agree with the statement that " cubic functions must have at least 1 x-intercept but not more than 3, whereas quadratic f
vladimir2022 [97]

Answer:

Yes, I agree

Step-by-step explanation:

For the cubic function

A cubic function is represented as:

f(x)=ax^3+bx^2+cx+d

A cubic function may have 1, 2 or 3 x intercepts. This is shown below

For 3 x intercepts

y = x^3 - x

Equate y to 0

x^3 - x = 0

Expand

x(x^2 - 1) = 0

Express x^2 - 1 as difference of two squares

x(x - 1)(x +1 ) = 0

<em>x = 0 or 1 or -1</em>

For 2 x intercepts

y = x^3 - x

y  =(x-5)^2)(x+7)

Equate y to 0

(x-5)^2(x+7) = 0

Expand

(x-5)(x-5)(x+7) = 0

<em>x= 5 or x = -7</em>

For 1 x intercept

y = x^3

Equate y to 0

x^3 = 0

Take cube roots of both sides

x = 0

It has been shown above that a cubic function may have 1, 2 or 3.

So, I agree to the statement

For the quadratic function

A quadratic function will not have any x intercept when the function can not be factorized;

E.g.

y = x^2 + x + 17

<em>The above function has no x intercept.</em>

A quadratic function will have at least 1 x intercept when the function can be factorized;

E.g.

y = x^2- 6x + 9

Equate y to 0

x^2- 6x + 9 = 0

Expand

x^2 - 3x - 3x + 9 = 0

(x - 3)(x-3) = 0

x = 3

We've shown that a quadratic may have no x intercept, and it may also have x intercept(s)

Hence, I agree to both statement

3 0
2 years ago
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