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gulaghasi [49]
3 years ago
8

What will be the effect on the graph of y = Ixl if x is replaced with -x?

Mathematics
1 answer:
s2008m [1.1K]3 years ago
5 0

Answer:

If x is replaced with -x the graph will stay the same because the absolute value makes 2 values so a negative number and a positive one.

Step-by-step explanation:

Go search it up on desmos.

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A local yoga studio
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Answer:

Let's call the first studio, yoga studio A.

Let's call the second studio, yoga studio B.

The equations:

Yoga Studio A: y=10x+55

Yoga Studio B: y=12.5x+25

So, for 12 classes:

Yoga Studio A: y=10(12)+55, y=175

Yoga Studio B: y=12.5(12)+25, y=175

These two numbers are equal, so Griffin is right.

For 10 classes:

Yoga Studio A: y=10(10)+55, y=155

Yoga Studio B: y=12.5(10)+25, y=150.

These two numbers are not equal, so Gigi is wrong.

Let me know if this helps!

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The lengths of two sides of a right triangle are 12 inches and 15 inches. What is the difference between the two possible length
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I get 10.2 for this answer
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Tom is digging a pool in the shape of a rectangular prism. He plans to make the pool 12 feet
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Step-by-step explanation:

Just add length x width x dept

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use the picture to write each ratio as a simplified fraction (how are you going to find the length of the third side?) show your
Butoxors [25]

Answer:

<h3>See below</h3>

Step-by-step explanation:

to figure out the ratios we must figure out the length of <u>hypotenuse</u> first to do so we can consider <u>Pythagoras</u><u> theorem</u> given by

\displaystyle  {a}^{2}  +   {b}^{2}  =  {c}^{2}

\displaystyle \implies c =  \sqrt{ {a}^{2} +  {b}^{2}  }

substitute:

\displaystyle c =  \sqrt{ {12}^{2} +  {9}^{2}  }

simplify squares:

\displaystyle c =  \sqrt{ 225 }

simplify square root:

\displaystyle c = 15

now recall that,

  • \displaystyle  \sin( \theta)  =  \frac{opp}{hypo}
  • \displaystyle\cos( \theta)  =  \frac{adj}{hypo}
  • \displaystyle   \tan( \theta)  =  \frac{opp}{adj}

the ratios with respect to angle w given by

  • \displaystyle  \sin( W)  =  \frac{12}{15}  =  \frac{4}{5}
  • \displaystyle  \cos(W)  =  \frac{9}{15}  =  \frac{3}{5}
  • \displaystyle  \tan( W)  =  \frac{12}{9}  =  \frac{4}{3}

the following ratio with respect to angle X

  • \displaystyle  \sin(X)  =  \frac{9}{15}  =  \frac{3}{5}
  • \displaystyle  \cos(X)  =  \frac{12}{15}  =  \frac{4}{5}
  • \displaystyle  \tan( X)  =  \frac{9}{12}  =  \frac{3}{4}
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3 years ago
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