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nydimaria [60]
3 years ago
11

How to solve 3&2/3+8+1&1/3

Mathematics
1 answer:
patriot [66]3 years ago
3 0

3 \frac{2}{3}  + 8 + 1 \frac{1}{3}
First, add the fractions because they already have a common denominator.

(3 \frac{2}{3}  + 1 \frac{1}{3} ) + 8
3 plus 1 equals 4. The fractions make 3/3 which equals 1. 4 plus 1 equals 5.
5 + 8
Your answer is 13.

Hope this helps!

:)
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Which sequence of transformations will verify that EFGH and quadrilateral EFGH and quadrilateral E'F'G'H are congruent?
levacccp [35]

D) EFGH moved onto E'F'G'H after rotating 180 counterclockwise around the origin and the reflecting across the y-axis.

<h3>How to carry out transformations?</h3>

From online resources gotten about this question, for quadrilateral EFGH and quadrilateral E'F'G'H to be congruent, what we must do first is to rotate 180° counterclockwise around the origin and then move EFGH onto E'F'G'H'.

The last step to get this proof of congruency is to reflect across the y-axis.

Read more about transformations at; brainly.com/question/4289712

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5 0
2 years ago
On a coordinate plane, a curved line labeled f of x with a minimum value of (1.9, negative 5.7) and a maximum value of (0, 2), c
77julia77 [94]

The graphed function, F(x), has a value greater than 0 over the intervals (-0.7, 0.76) and (0.76,  ∞) . F(x) > 0 over the intervals (-0.7, 0.76) and (0.76, ∞) is the correct statement [Fourth choice].

About a Graphed Function

The function graph of an object F stands for the set of all points in the plane that are (x, f(x)). The graph of f is also known as the graph of y = f. (x). The graph of an equation is thus a specific example of the graph of a function. A graphed function is a function that has been drawn out on a graph.

It is evident from the attached graph that the supplied function exceeds 0 for the following range:

-0.7 < F(x) < 0.76

And, 0.76 < F(x) < ∞

As a result, the intervals for which the given graphed function, F(x) is greater than 0 are as follows,

(-0.7, 0.76) and (0.76, ∞)

Learn more about a graphed function here:

brainly.com/question/27757761

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3 0
1 year ago
Three vertices of the trapezoid are A(4d,4e), B(4f,4e), and C(4g,0). The fourth vertex lies on the origin. Find the midpoint of
satela [25.4K]
We have that

point C and point D have y = 0-----------> (the bottom of the trapezoid).

point A and point B have y = 4e ---------- > (the top of the trapezoid)

the y component of  midpoint would be halfway between these lines
 y = (4e+ 0)/2 = 2e. 

<span>the x component of the midpoint of the midsegment would be halfway between the midpoint of AB and the midpoint of CD.

x component of midpoint of AB is (4d + 4f)/2.
x component of midpoint of CD is (4g + 0)/2 = 4g/2.
x component of a point between the two we just found is
[(4d + 4f)/2 + 4g/2]/2 = [(4d + 4f + 4g)/2]/2 = (4d + 4f + 4g)/4 = d + f + g. 

</span>therefore

the midpoint of the midsegment is (d + f + g, 2e)
8 0
3 years ago
Find the value of <br><img src="https://tex.z-dn.net/?f=%20log_%7B8%7D%5E%7B512%7D%20" id="TexFormula1" title=" log_{8}^{512} "
valina [46]
Answer: 3
Explanation: logarithm base 8 of 512 is 3
8 0
2 years ago
The two way frequency table shows what a group of students did during the summer. Which statement is true related to the table?
ratelena [41]

Answer:

That statement is true which relates to what activity was taken by most of the students of different categories in that particular group during the summers.

Step-by-step explanation:

A two-way frequency table (likewise called a possibility table) is a valuable instrument for inspecting connections between downright factors. The passages in the cells of a two-way table can be frequency checks or relative frequencies (simply like a single direction table). Two-way frequency tables show what number of information focuses fit in every classification.  

Assume you direct a review where you pose every individual two inquiries. When you have wrapped up the overview, you will have two bits of information from every individual. At whatever point you have two bits of information from every individual, you can arrange the information into a two-way frequency table.

8 0
3 years ago
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