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3 years ago

Christy dove to a depth of 12 feet below the surface of the water write the depth as an integer

1 answer:

4 0

If we use the surface of the water as our frame of reference, then Christy's vertical position could be represented by -12 ft.

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Describe how to create equivalent ratios

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Since a ratio can also be written to look like a fraction, you can use your knowledge of creating equivalent fractions to this to create equivalent ratios. i.e: 5:10 can be written as 5/10, you can simplify it to 1/2 (1:2) or multiply it by 2/2 to get 10/20 (10:20).

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3 years ago

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2 years ago

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Goals scored by a hockey team in successive matches are 5,7,4,2,4,0,5,5 and 3. What is the number of goals, the team must score

Stels [109]

Answer:

Step-by-step explanation:

Total goals /total no. of matches = 4

5+7+4+2+4+0+5+5+3+x / 10 = 4

35 + x = 4 × 10

x = 40 - 35

x = 5

So, the team must score 5 inorder to get the average of 4 goals per match.

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1 year ago

What is the answer to number 8.

Viktor [21]

Its 20. |-2|+4-(-2)×(7). This simplifies to 2+4+(2×7)

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3 years ago

Find the midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9)

JulsSmile [24]

The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

<u>Solution:</u>

Given, two points are (-6, 6) and (-3, -9)

We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)$ is given by:

$\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

$\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9$

Plugging in the values in formula, we get,

$\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}$

Hence, the midpoint of the segment is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

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2 years ago