Answer:
Step-by-step explanation:
Let A = R−{0}, the set of all nonzero real numbers, and consider the following relations on A × A.
Given that (a,b) R (c,d) if 
Or (a,b) R (c,d) if determinant
![\left[\begin{array}{ccc}a&b\\c&d\end{array}\right] =0](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%20%3D0)
a) Reflexive:
We have (a,b) R (a,b) because ab-ab =0 Hence reflexive
b) Symmetric
(a,b) R (c,d) gives ad-bc =0
Or da-cb =0 or cb-da =0 Hence (c,d) R(a,b). Hence symmetric
Answer:
- The sequence of transformations that maps triangle XYZ onto triangle X"Y"Z" is <u>translation 5 units to the left, followed by translation 1 unit down, and relfection accross the x-axis</u>.
Explanation:
By inspection (watching the figure), you can tell that to transform the triangle XY onto triangle X"Y"Z", you must slide the former 5 units to the left, 1 unit down, and, finally, reflect it across the x-axys.
You can check that analitically
Departing from the triangle: XYZ
- <u>Translation 5 units to the left</u>: (x,y) → (x - 5, y)
- Vertex X: (-6,2) → (-6 - 5, 2) = (-11,2)
- Vertex Y: (-4, 7) → (-4 - 5, 7) = (-9,7)
- Vertex Z: (-2, 2) → (-2 -5, 2) = (-7, 2)
- <u>Translation 1 unit down</u>: (x,y) → (x, y-1)
- (-11,2) → (-11, 2 - 1) = (-11, 1)
- (-9,7) → (-9, 7 - 1) = (-9, 6)
- (-7, 2) → (-7, 2 - 1) = (-7, 1)
- <u>Reflextion accross the x-axis</u>: (x,y) → (x, -y)
- (-11, 1) → (-11, -1), which are the coordinates of vertex X"
- (-9, 6) → (-9, -6), which are the coordinates of vertex Y""
- (-7, 1) → (-7, -1), which are the coordinates of vertex Z"
Thus, in conclusion, it is proved that the sequence of transformations that maps triangle XYZ onto triangle X"Y"Z" is translation 5 units to the left, followed by translation 1 unit down, and relfection accross the x-axis.
A is the closest, hope this helped
Area is 50 m^2
5 x 3 = 15
7 x 5 = 35
35 + 15 = 50 m^2
Pretty sure it’s 1/9
1/3 = 3/9
1/9 is 1/3 of 1/3
Answer= 1/9
