Write two equations with the given information:
1) x = 2y ( x is twice the value of y)
2) x + y = 42
Replace x in the second equation with the value of x in the first equation:
2y + y = 42
Simplify:
3y = 42
Divide both sides by 3:
y = 42 / 3
y = 14
Now we have the value for Y, solve for x by replacing y with 14:
x = 2y
x = 2(14)
x = 28
X = 28 and y = 14
Answer: 195.5 or 12 7/32
Step-by-step explanation:
There is no letter tetha in the table so I use α instead. However it is not sence to final result.
The expression is:
(sinα+cosα)/(cosα*(1-cosα))
Lets divide the nominator and denominator by cosα
(sinα/cosα+cosα/cosα)/(cosα*(1-cosα)/cosα)= (tanα+1)/(1-cosα)=
=(8/15+1)/(1-cosα)= 23/(15*(1-cosα)) (1)
As known cos²α=1-sin²α (divide by cos²α both sides of equation)
cos²a/cos²α=1/cos²α-sin²α/cos²α
1=1/cos²α-tg²α
1/cos²α=1+tg²α
cos²α=1/(1+tg²α)
cosα=sqrt(1/(1+tg²α))= +-sqrt(1/(1+64/225))=+-sqrt(225/(225+64))=
=+-sqrt(225/289)=+-15/17 (2)
Substitute in (1) cosα by (2):
1st use cosα=15/17
1) 23/(15*(1-cosα)) =23/(15*(1-15/17))= 23*17/2=195.5
2-nd use cosα=-15/17
2)23/(15*(1-cosα)) =23/(15*(1+15/17))= 23*17/32=12 7/32
Answer:
the answer is d
<em>The square root property should have been applied to both complete sides of the equation instead of to select variables.
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Step-by-step explanation: i just took the test on edge
Answer:
60in
Step-by-step explanation:
Given data
Length= 24 in
Width = 18 in
Diagonally, we need to find using the Pythagoras theorem
D^2= L^2+W^2
D^2= 24^2+18^2
D^2= 576+324
D^2= 900
Square both sides
D= √900
D= 30 in
For both sides
=30*2= 60in
