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viktelen [127]
3 years ago
5

Item 8 Solve for x. Use the quadratic formula. 2x2−5x−9=0 Enter the solutions, in simplified radical form, in the boxes.

Mathematics
2 answers:
Lubov Fominskaja [6]3 years ago
7 0

Answer:

5+√97/4

Also 5-√97/4

Step-by-step explanation:

The Quadratic formula is x=-b+-√b^2-4ac/2a

This means that we should plug the values for A B AND C into the formula

We can work out that

<u><em>A = 2</em></u>

<u><em>B=-5</em></u>

<u><em>C=-9</em></u>

Once we have put these into the formula we get

5+√97/4 (all over 4) aka 3.71

Also 5-√97/4 (all over 4) aka -1.21

Dimas [21]3 years ago
3 0

Answer:

\large\boxed{x=\dfrac{5-\sqrt{97}}{4}\ or\ x=\dfrac{5+\sqrt{97}}{4}}

Step-by-step explanation:

\text{Let}\ ax^2+bx+c=0\\\\\text{The quadratic formula:}\\\\\Delta=b^2-4ac\\\\\text{If}\ \Delta>0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt\Delta}{2a}\\\\\text{If}\ \Delta=0,\ \text{then the equation has one solution}\ x=\dfrac{-b}{2a}\\\\\text{If}\ \Delta

\text{The equation}\ 2x^2-5x-9=0\\\\a=2,\ b=-5,\ c=-9\\\\\Delta=(-5)^2-4(2)(-9)=25+72=97>0\\\\\sqrt\Delta=\sqrt{97}\\\\x_1=\dfrac{-(-5)-\sqrt{97}}{2(2)}=\dfrac{5-\sqrt{97}}{4}\\\\x_2=\dfrac{-(-5)+\sqrt{97}}{2(2)}=\dfrac{5+\sqrt{97}}{4}

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