Let us calculate the median; the 6th observation is 20, so it is 20. We need the 6th observation so that out of the 11 observations we have 5 above the median and 5 below (or equal). We also have that then Q1 is the median of the lowest 5 observations, hence 19 (14,16,19,19,20, the 3rd observation is 19). Similarly, we get that the median for the upper half of the observations, Q3 namely, is 22 (21,21,22,22,23, the 3rd observation is 22). Thus, the interquartile range is 3=Q3-Q1. According to our calculations, all observations are wrong.
The speed of this:
70 miles per hour
1 hour = 60 minutes
70/60 = 7/6
around 1 1/6 mile per minute
hope this helps
1yd is 12 ft
So do 12-1=11.
11 is the answer
The answer is D :) II hope that this helps and if you need a bigger description I can help
Answer:
c = 2
Step-by-step explanation:
26 - (2c + 4) = 2(c+6) + c
26 - 2c + 4 = 2c + 12 + c
26 - 4 - 12 = 2c + 2c + c
10 = 5c
2 = c
