Question

Write the equation of the circle with center (3,2) and with (9,3) being a point on the circle

Answer 1

Answer:

$(x-3)^2 + (y-2)^2 = 37$

Step-by-step explanation:

To write the equation of a circle, use the formula $(x-h)^2+(y-k)^2 = r^2$ where the center of the circle is (h, k).

This means the equation is $(x-3)^2 + (y-2)^2 = r^2$.

Find the radius r by finding the distance between (3,2) and (9,3) using the distance formula.

$d = \sqrt{(9-3)^2 + (3-2)^2} =\sqrt{6^2 + 1^2} =\sqrt{36+1} =\sqrt{37}$

Since the radius is √37 and therefore $r^2 = 37$.

The equation is $(x-3)^2 + (y-2)^2 = 37$.