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Xelga [282]
3 years ago
5

What is the value of |B| – |A|? A. 4 B. –10 C. 10 D. –4

Mathematics
2 answers:
Elena L [17]3 years ago
5 0

Answer:

A. 4

Step-by-step explanation:

We can look at the number line and find B and A

we get

B=-7

A=3

now, we can find |B| and |A|

|B|=|-7|=7

|A|=|3|=3

now, we can find

|B|-|A|

now, we can plug values

|B|-|A|=7-3

|B|-|A|=4

So,

option-A

makkiz [27]3 years ago
4 0

Hey there!

  • B = -7
  • A=3
  • The negative 7 becomes a positive; +3 stays the same
  • \bold{|7|-|3|}
  • \bold{7-3=4}
  • \boxed{\boxed{\bold{Answer:A.4}}}

Good luck on your assignment and enjoy your day!

~\bold{LoveYourselfFirst:)}



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Answer:

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Step-by-step explanation:

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An object is traveling around a circle with a radius of 10 cm. If in 20 seconds a central angle of 1/3 radian is swept out, what
arsen [322]
Usually, Δ stands for a difference: if you have two quantities a₂ and a₁, their difference a₂-a₁ can be shortened as Δa.

This said, your formula is not set up correctly: the linear speed can be found with the formula:
v = ω·r
where r is the radius and <span>ω is the angular frequency, which is given by:
</span>ω = Δα / Δt
Substituting this into the one above, you find the correct formula:
<span>v = (Δα / Δt) · r

The problem gives you directly </span>Δα, which is 1/3 rad, because does not say at what angle the point started moving and at what angle it stopped.
Similarly, for the time you have Δt, which is 20 s.

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3 years ago
The equation for bryce's running rate is y=5x and for Laila it is y=8x. Who is running faster?
Nonamiya [84]

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Step-by-step explanation:

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3 years ago
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ElenaW [278]
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2 years ago
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A car is on a driveway that is inclined 10 degrees to the horizontal. A force of 490 lb is required to keep the car from rolling
lara31 [8.8K]

Answer:

a) weight  of the car = 2816,1 lbs

b) 2773 lbs

Step-by-step explanation:

The equilibrium force is 490 lbs. That force keep the car at rest, then

∑ Fy  =  0     and  ∑Fx  =  0

Forces acting on the car:

The external force   490 lbs

weight of the car   uknown

Normal force

sin∠10°  =  0,174

cos∠10° = 0.985

∑Fx  =  0         mg*sin10°- 490 = 0      ∑Fy =  0      mg*cos10° - N  =  0

mg*0,174= 490

mg  =  490 / 0,174

mg = 2816,1 lbs

weight  of the car = 2816,1 lbs

The Normal force

mg*cos10° - N  =  0        2816,1 * 0,985 = N

N = 2773 lbs

Then equal force in magnitude and in opposite direction will car exets on the driveway

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3 years ago
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