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PolarNik [594]
3 years ago
7

Please help, I don’t get the question.

Physics
1 answer:
aalyn [17]3 years ago
6 0

All you have to do is get the culmative effect of the forces by predicting the direction in which each object will move. Just write down what you know and put down questions for your teacher.

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When observed from earth, how many oscillations does the pendulum on the spaceship undergo compared to the pendulum on earth in
Roman55 [17]

Answer: it’s Fewer oscillations.

Explanation:

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Explain what surface tension is.
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3 years ago
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Notice that the speed halfway down is not half the final speed. Another interesting point is that the final answer doesn't depen
ValentinkaMS [17]

Answer:

its speed is insignificant before the diver's speed change, so the result does not change

Explanation:

In this exercise of conservation of the momentum, the system is formed by the diver and the Earth

initial instant (before jumping)

       p₀ = 0

final instant (after jumping)

      p_{f} = m v + M v²

how momentum is conserved

        p₀ = p_{f}

        0 = m v + M v²

         v² = m / M v

since the mass of the Earth is M = 10²⁴ kg

   its speed is insignificant before the diver's speed change, so the result does not change

7 0
3 years ago
Where is the best place to put pfds while you are out on your boat?
Alexeev081 [22]
The best place to put PFDs while you are out on your boat is at the top deck of your boat. PFDs must be placed at an area where it is easily accessible, especially in times of accidents, without any unnecessary gear or objects covering the PFDs, but it is best to wear a life jacket during the whole duration of the boat trip.
3 0
3 years ago
One strategy in a snowball fight is to throw a snowball at a high angle over level ground. While your opponent is watching the f
Andreas93 [3]

Answer:

Part a)

\theta_2 = 15 degree

Part b)

\Delta t = 2.88 s

Explanation:

Part a)

In order to have same range for same initial speed we can say

R_1 = R_2

\frac{v^2 sin2\theta_1}{g} = \frac{v^2 sin2\theta_2}{g}

so after comparing above we will have

\theta_1 = 90 - \theta

so we have

75 = 90 - \theta_2

\theta_2 = 15 degree

Part b)

Time of flight for the first ball is given as

T_1 = \frac{2vsin\theta}{g}

T_1 = \frac{2(20)sin75}{9.81}

T_1 = 3.94 s

Now for other angle of projection time is given as

T_2 = \frac{2(20)sin15}{9.81}

T_2 = 1.05 s

So here the time lag between two is given as

\Delta t = T_1 - T_2

\Delta t = 3.94 - 1.05

\Delta t = 2.88 s

5 0
3 years ago
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