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zlopas [31]
2 years ago
14

In an experiment to estimate the acceleration due to gravity, a student drops a ball at a distance of 1 m above the floor. His l

ab partner measures the time it takes to fall and obtains an estimate of 0.46 s.
(a) What do they estimate the acceleration due to gravity to be?
(b) Let s be the ball's position relative to the floor. Using the value of the acceleration due to gravity that they obtained, and assuming that the ball is released at t = 0. determines (in m) as a function of time.
Physics
1 answer:
anyanavicka [17]2 years ago
3 0

Answer:

9.45179\ m/s^2

s=4.725895t^2

Explanation:

t = Time taken = 0.46

u = Initial velocity

v = Final velocity

s = Displacement = 1 m

a = Acceleration

s=ut+\frac{1}{2}at^2\\\Rightarrow 1=0\times 0.46+\frac{1}{2}\times a\times 0.46^2\\\Rightarrow a=\frac{1\times 2}{0.46^2}\\\Rightarrow a=9.45179\ m/s^2

The acceleration due to gravity is 9.45179 m/s²

s=ut+\frac{1}{2}at^2\\\Rightarrow s=\frac{1}{2}at^2\\\Rightarrow s=\dfrac{1}{2}9.45179t^2\\\Rightarrow s=4.725895t^2

The function is s=4.725895t^2

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