Ask question

Ask question

All categories

3 years ago

13

Mars, which has a radius of 3.4 × 106 m and a mass of 6.4 × 1023 kg, orbits the Sun, which has a mass of 2.0 × 1030 kg at a dist

ance of 2.3 × 1011 m. Which is greater, the tangential speed of Mars’s rotation or revolution?

2 answers:

Flura [38]3 years ago

8 0

The correct answer is: Revolution (The tangential speed of Mars' revolution is greater than that of Mars' rotation).

Explanation:

Given data:

Radius-of-Mars = r = $3.4 * 10^6$ m

Distance-between-Sun-and-Mars = d = $2.3 * 10^{11}$ m

Now let us first calculate the Mars' rotation:

One complete rotation of Mars = 2πr = 2π( $3.4*10^6$ ) = $21.36 * 10^6$ m

Tangential speed of Mars' rotation (by taking 24hours 37 minutes in seconds (88620s)—as Mars takes that many seconds to complete one rotation) = $\frac{21.36 * 10^6m}{88620} = 241.02 \frac{m}{s}$

Now let's calculate the Mars' revolution (around Sun):

One complete revolution of Mars around Sun = 2πd = 2π( $2.3 * 10^{11}$ ) = $1.45 * 10^{12}$ m

Tangential speed of Mars' revolution (by taking 687 days in seconds (59356800s)—since Mars takes 687days to complete one revolution)= $\frac{1.45 * 10^{12}m}{59356800s} = 24.42 * 10^{3}\frac{m}{s}$

So we can see that the tagential speed of:

Revolution > Rotation

$24.42 * 10^{3}\frac{m}{s}$ > $241.02\frac{m}{s}$

Hence, the correct answer is Revolution.

Arisa [49]3 years ago

6 0

The correct answer is: revolution

You might be interested in

Consider the video tutorial you just watched. Suppose that we duplicate this experimental setup in an elevator. What will the sp

zloy xaker [14]

Explanation:

if the elevator is moving upward with the constant speed the spring scale will read 18 N which is the mass of each of the two blocks attached by separate springs to the scale at opposite ends.

4 0

3 years ago

a piece of metal with a mass of 15.3 grams has a temperature of 50.0°C. When the metal is placed in 80.2 grams of water at 21.0°

AleksAgata [21]

Answer:

1.21

Explanation:

Heat rise in the body happens due to heat supplied by water to the body.

Heat rise in body = m₁ c₁ ΔT₁

Where m₁ is mass of body and c₁ is its specific heat of body

Heat lost from water to the body = m₂ c₂ ΔT₂

Where m₂ is mass of water and c₂ is its specific heat of water ( c₂ =1 (since water))

Equating both:

15.3 x c₁ x 4.3 = 80.2 x 1 x 4.3

⇒ c₁ = 80.2 / (15.3 x 4.3) = 1.21

6 0

3 years ago

Read 2 more answers

Would a bond between potassium and iodine most likely be covalent or ionic? Explain your answer

Ugo [173]

A covalent bond is between two nonmetals. An ionic bond is between a metal and a nonmetal. Potassium is a metal and iodine is a nonmetal, so their bond would most likely be ionic.

4 0

3 years ago

Plane-polarized light is incident on a single polarizing disk, with the direction of E0 parallel to the direction of the transmi

Vladimir [108]

Answer: $65.9^{\circ}$

Explanation:

Given

Intensity must be reduced by a factor of 6

Intensity is given by $I=I_o\cos ^2\theta\\$

Substitute $I$ by $\frac{I_o}{6}$

$\Rightarrow \dfrac{I_o}{6}=I_o\cos ^2\theta\\\\\Rightarrow \cos^2\theta =\dfrac{1}{6}\\\\\Rightarrow \cos \theta=\dfrac{1}{\sqrt{6}}\\\\\Rightarrow \theta=65.9^{\circ}$

So, the disk must be rotated by an angle of $65.9^{\circ}$ .

7 0

2 years ago

Review. As an astronaut, you observe a small planet to be spherical. After landing on the planet, you set off, walking always st

anyanavicka [17]

To find the mass of the planet we will apply the relationship of the given circumference of the planet with the given data and thus find the radius of the planet. From the kinematic equations of motion we will find the gravitational acceleration of the planet, and under the description of this value by Newton's laws the mass of the planet, that is,

The circumference of the planet is,

$\phi = 25.1m$

Under the mathematical value the radius would be

$\phi = 2\pi r$

$r = \frac{25}{2\pi}$

$r = 3.9788km$

Using second equation of motion

$x = \frac{1}{2} at^2$

Replacing the values given,

$1.4 = \frac{1}{2} a (29.2)^2$

Rearranging and solving for 'a' we have,

$a = 0.003283m/s^2$

Using the value of acceleration due to gravity from Newton's law we have that

$a = \frac{GM}{r^2}$

Here,

r = Radius of the planet

G = Gravitational Universal constant

M = Mass of the Planet

$\frac{(6.67*10^{-11})*M}{(3.9788*10^3)^2} = 0.003283$

$M = 7.79201*10^{14}kg$

Therefore the mass of this planet is $7.79201*10^{14}kg$

5 0

4 years ago