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matrenka [14]
3 years ago
6

An organism has 12 chromosomes in its sex cell. It undergoes a process producing four daughter cells, each with 6 chromosomes. W

hat is the process?
Biology
1 answer:
astraxan [27]3 years ago
6 0
Meiosis.
Meiosis results in four cells of the original, each with a halved amount of chromosomes, you could say.
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What part of the respiratory system exchanges gases between the respiratory system and the circulatory system?.
kirill [66]

Answer:

The lungs

Explanation:

The lungs in your body get filled up with air when you inhale. There are blood vessels around the alveoli in your lungs (which are tiny air sacs that hold the air). The blood vessels absorb the oxygen in a process called diffusion where gas diffuses through the one cell thick wall of the alveoli into the blood vessels. The circulatory system then pumps the blood around your body to the cells that need the oxygen.

8 0
2 years ago
Someone please helppp!
Sauron [17]

Answer:

D) the presence or absence of a Nucleus

Explanation:

A Nucleus is present in a Eukaryotic cell. A Nucleotide is present in a Procaryotic cell. If there is a nucleus present, it is a Eukaryotic cell

3 0
3 years ago
Differences in female and male reproductive biology have led to different mating strategies for men and women. This is an exampl
Citrus2011 [14]

Answer: Evolutionary

Explanation:

Evolution of the male and female reproductive organs is necessary for the advancement of mating strategies that range from simple to complex living beings. This is a kind of adaptation those which have phenotypic characteristics favourable to attract the mates will reproduce the offspring. These traits will be passed on to the progeny and evolution of the species will take place.

6 0
3 years ago
In a population of Mendel's garden peas, the frequency of the dominant A (yellow flower) allele is 80%. Let p represent the freq
k0ka [10]

Answer:

C) 64% AA, 32% Aa, 4% aa

Explanation:

The frequency of dominant allele A is = 80% = 0.8

Since the population is in Hardy-Weinberg equilibrium, p+ q =  1

Here, p= frequency of dominant allele

q = frequency of recessive allele

Given, p= 0.8

So, q = 1-p = 1-0.8= 0.2

Frequency of genotype AA = p2 = 0.8 x 0.8 = 0.64 = 64%

Frequency of genotype aa = q2 = 0.2 x 0.2 = 0.04 = 4%

Frequency of genotype Aa = 2pq = 2 x 0.8 x 0.2 = 0.32 = 32%

5 0
3 years ago
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