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3 years ago

Rewrite 140^1/8 in radical form.

Mathematics

2 answers:

MrRa [10]3 years ago

6 0

You simply put the denomintor on the outside of the radical form.

The answer is 8√140.

notka56 [123]3 years ago

4 0

140^1/8 = $\sqrt[8]{140}$

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Write the equation of the line of best fit using the slope-intercept formula $y = mx + b$. Show all your work, including the poi

Dennis_Churaev [7]

Answer:

$y=\frac{5}{7}x+\frac{135}{7}$

Step-by-step explanation:

You only need two points on a line to find the equation for that line.

We are going to use 2 points that cross that line or at least come close to. You don't have to use the green points... just any point on the line will work. You might have to approximate a little.

I see ~(67.5,67.5) and ~(64,65).

Now once you have your points, we need to find the slope.

You may use $\frac{y_2-y_1}{x_2-x_1}$ where $(x_1,y_1) \text{ and } (x_2,y_2)$ are points on the line.

Or you can line up the points vertically and subtract then put 2nd difference over 1st difference.

Like this:

( 64 , 65 )

-( 67.5, 67.5 )

--------------------

-3.5 -2.5

So the slope is -2.5/-3.5=2.5/3.5=25/35=5/7.

Now use point-slope form to find the equation:

$y-y_1=m(x-x_1)$ where $m$ is the slope and $(x_1,y_1)$ is a point on the line.

$y-65=\frac{5}{7}(x-64)$

Distribute:

$y-65=\frac{5}{7}x-\frac{5}{7}\cdot 64$

Simplify:

$y-65=\frac{5}{7}x-\frac{320}{7}$

Add 65 on both sides:

$y=\frac{5}{7}x-\frac{320}{7}+65$

Simplify:

$y=\frac{5}{7}x+\frac{135}{7}$

6 0

3 years ago

What would the answer be

ArbitrLikvidat [17]

Answer:

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Step-by-step explanation:

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3 years ago

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galben [10]

Answer:

i would say around 61.54%

Step-by-step explanation:

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3 years ago

Explain how you could use the construction tool or a compass and straightedge to create a line segment that is twice as long as

ohaa [14]

Answer: Use a compass to measure the length of AB. Draw an arc from point B (or point A) with that distance. Extend line AB through that arc and label the intersection as point C. AC is twice the length of AB.

5 0

3 years ago

Please help me to solve this . Thank you so much .

worty [1.4K]

Answer:

a) N

b) L

c) area I

d) area II

e) area VI

Step-by-step explanation:

a) the points that are 2cm from R are Q, N, M, S. Then, points that are 4cm from P are K, N, R. So, the only one point that works for both is N.

b) the points that are >2cm from R are P, K, L, T. We do not count those are exactly 2cm from R. Then, points that are 4cm from T are R, M, L. Ans is L.

c) <4cm from P, are area I and II. Then area that are >2cm from R are I, VI, and V. So, the only area that works for both is I.

d) <2cm from R, are areas II, III, and IV. Then, <4cm from P, are areas I and II. So, the only one works for both is area II.

e) >4cm from T, are areas I, II, III, VI. Then, >4cm from P, are III, IV, V, VI. Finally, >2cm from R, are areas I, VI, V. The only one that works for all three conditions is area VI.

5 0

3 years ago