The line through (6,-6) with slope 1/2 in point-slope form ?

Mathematics

1 answer:

aleksandrvk [35]2 years ago

8 0

Answer: $y + 6 = \frac{1}{2}(x - 6)$

Step-by-step explanation:

Point-slope formula: $y - y1 = m(x - x1)$

Plug in the numbers: $y - -6 = \frac{1}{2}(x-6)$

Clear the double negatives: $y + 6 = \frac{1}{2}(x - 6)$

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3x^2(x^3-1)+2x^3(2x^2+2) <br> Whats the simplified answer?

ahrayia [7]

Answer:

$\large\boxed{7x^5+4x^3-3x^2}$

Step-by-step explanation:

$3x^2(x^3-1)+2x^3(2x^2+2)\qquad\text{use the distributive property:}\ a(b+c)=ab+ac\\\\=(3x^2)(x^3)+(3x^2)(-1)+(2x^3)(2x^2)+(2x^3)(2)\qquad\text{use}\ a^na^m=a^{n+m}\\\\=3x^{2+3}-3x^2+4x^{3+2}+4x^3\\\\=3x^5-3x^2+4x^5+4x^3\qquad\text{combine like terms}\\\\=(3x^5+4x^5)-3x^2+4x^3\\\\=7x^5+4x^3-3x^2$

4 0

3 years ago

Find K such that the points (-2, 5), (2, 8) and (6, K) are collinear.

damaskus [11]

Answer:

k = 11

Step-by-step explanation:

let the points be A(-2,5), B(2,8), C(6,K).

for the points to be collinear slope of line AB maust be equal to line BC.

slope of line AB = $\frac{8-5}{2+2}=\frac{3}{4}$

slope of line BC = $\frac{k-8}{6-2}=\frac{k-8}{4}$

therefore $\frac{k-8}{4}= \frac{3}{4}$

therefore k = 8 + 3

k = 11

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3 years ago

Identify the segment bisector of MN Then find MN.<br> ????????? Helppp pleaseee

enot [183]

Given:

The figure.

To find:

The segment bisector of MN and value of MN.

Solution:

From the given figure it is clear that ray RP,i.e., $\overrightarrow {RP}$ is the segment bisector of MN because it divides segment MN in two equal parts.