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valentinak56 [21]
4 years ago
6

Two ropes in a vertical plane exert equal-magnitude forces on a hanging weight but pull with an angle of 72.0° between them. Wha

t pull does each rope exert if their resultant pull is 372 N directly upward?

Physics
1 answer:
Yanka [14]4 years ago
5 0

Answer:

T1 = 250.57[N] and T2 = 250.57[N]

Explanation:

First we have to extract all the information they give us about the problem, then make a free body diagram with all the forces that act on the body.

In the attached image we can see the free body diagram with the respective forces.

By summing up forces on the Y-axis, we can find the T1 and T2 force, these forces are equal since it is an initial condition of the problem. This equation can therefore be cleared.

The equations and analysis can be seen in the attached image

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A dog in an open field runs 11.0 m east and then 28.0 m in a direction 49.0 ∘ west of north. In what direction must the dog then
Ede4ka [16]

Answer:

\theta=19.03 SE

Explanation:

From the question we are told that:

d_1=11.0m East

d_2=28.0m 49 \textdegree west\ north

d_3=10m south

Generally the equation for Resolutions is mathematically given by

d_x=-11-(-28sin49)

d_x=10.132m

Where

d_y=-11-(28cos49)

d_y=-29.37m

Generally the equation for Direction is mathematically given by

\theta=tan^{-1}(\frac{dx}{dy})

\theta=tan^{-1}(\frac{10.132}{29.37})

\theta=19.03 SE

7 0
3 years ago
Two physics students shoot a water-bottle rocket from a 1 m tall stand. They calculate that rocket will travel with the given fo
Kitty [74]

Answer:

2 secs; 65 feet

Explanation:

The function guiding the water bottle is given as:

f(x) = -16t² + 64t + 1

The bottle will reach maximum height when velocity, df/dt (velocity is the first derivative of distance) = 0.

Therefore:

df/dt = 0 = -32t + 64

=> 32t = 64

t = 64/32 = 2 seconds

This is the time it will take to reach the maximum height.

To find this height, we insert t = 2 into the function f(x):

f = -16(2)² + 64(2) + 1

f = -(16 * 4) + 128 + 1

f = -64 + 128 + 1

f = 65 ft

Its maximum height is 65 ft.

7 0
3 years ago
Read 2 more answers
Suppose 8.41 moles of a monatomic ideal gas expand adiabatically, and its temperature decreases from 395 to 279 K. Determine (a)
sergeinik [125]

Answer:

a) W=12166.20876 J

b) U= -12166.20876 J

Explanation:

No. of moles, n = 8.41

Change of temperature, ΔT = T1 - T2

                                         = 395 - 279

                                         = 116 K

For monatomic gas, γ = 5/3

γ -1 = 2 /3

Solution:

(a)

Work done,W= \frac{nR}{\gamma-1}(T_1-T_2)

plugging values we get

W= \frac{8.314\times8.41}{2/3}(116)

Ans:   12166.20876 J

Work done, W = + 12166.20876 J

(b)

From first law of thermodynamics, dQ = U + W

but, dQ = 0 ( adiabatic process)

Hence, U = - W

                 = - 12166.20876 J

Ans:

Change in internal energy, U = - 12166.20876 J

8 0
3 years ago
30 points!
vlada-n [284]

Answer:

Since strong nuclear forces involve only nuclear particles (not electrons, bonds, etc)  items 3 and 4 are eliminated.

Again item 2 refers to bonds between atoms and is eliminated.

This leaves only item 1.

Nuclear forces are very short range forces between components of the nucleus.

Weak nuclear forces are trillions of times smaller than strong forces.

Gravitational forces are much much smaller than the weak nuclear force.

6 0
3 years ago
Two basketball players are essentially equal in all respects. (They are the same height, they jump with the same initial velocit
ser-zykov [4K]
The reaction time of Boris is t(r), so before that, Boris will not have jumped. Thus, H(b)(t) = 0
The vertical displacement will simply be
D(t) = H(a)(t)
7 0
3 years ago
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