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Anna71 [15]
3 years ago
10

Dr stones is investigating the parts of the brain that are activated when people watch frightening movies dr. Stone is investiga

ting using which perspective
Physics
1 answer:
grigory [225]3 years ago
5 0

Dr Stones investigated this part of the brain using the perspective of a patient.

I don't know the answer choices.

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250

Explanation:

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Describe the role of observations in scientific endeavor and explain the characteristics of good observations.
koban [17]
Observations are used in order to collect data and record a variety of interesting or useful key points about the subject or specimen in observation. These observations, if made well, can be recorded and used to supplement a hypothesis. 
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Lol somebody tell me the answer ill also give 5 stars
AnnyKZ [126]

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i believe it's carbon. i may be wrong. but i haven't done atoms in almost 2 years. sorry if it's wrong. :)) hava good day

Explanation:

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To prevent accidental electric shock, most electrical equipment is A. painted. B. isolated. C. coated. D. grounded.
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D. It is Grounded below ground 
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A satellite that goes around the earth once every 24 hours iscalled a geosynchronous satellite. If a geosynchronoussatellite is
alexgriva [62]

Answer:

R=4.22*10⁴km

Explanation:

The tangential speed v of the geosynchronous satellite is given by:

v=\frac{2\pi R}{T}

Because 2\pi R is the circumference length (the distance traveled) and T is the period (the interval of time).

Now, we know that the centripetal force of an object undergoing uniform circular motion is given by:

F_c=\frac{mv^{2} }{R}

If we substitute the expression for v in this formula, we get:

F_c=\frac{m(\frac{2\pi R}{T})^{2}}{R}=\frac{4m\pi ^{2}R}{T^{2}}

Since the centripetal force is the gravitational force F_g between the satellite and the Earth, we know that:

F_g=\frac{GMm}{R^{2}}\\\\\implies \frac{GMm}{R^{2}}=\frac{4m\pi ^{2}R}{T^{2}}\\\\R^{3}=\frac{GMT^{2}}{4\pi^{2}} \\\\R=\sqrt[3]{\frac{GMT^{2}}{4\pi^{2}} }

Where G is the gravitational constant (G=6.67*10^{-11} Nm^{2}/kg^{2}) and M is the mass of the Earth (M=5.97*10^{24}kg). Since the period of the geosynchronous satellite is 24 hours (equivalent to 86400 seconds), we finally can compute the radius of the satellite:

R=\sqrt[3]{\frac{(6.67*10^{-11}Nm^{2}/kg^{2})(5.97*10^{24}kg)(86400s)^{2}}{4\pi^{2}}}\\\\R=4.22*10^{7}m=4.22*10^{4}km

This means that the radius of the orbit of a geosynchronous satellite that circles the earth is 4.22*10⁴km.

5 0
4 years ago
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