Question

A dog in an open field runs 11.0 m east and then 28.0 m in a direction 49.0 ∘ west of north. In what direction must the dog then run to end up 11.0 m south of her original starting point?

Answer 1

Answer:

$\theta=19.03 SE$

Explanation:

From the question we are told that:

$d_1=11.0m East$

$d_2=28.0m 49 \textdegree west\ north$

$d_3=10m south$

Generally the equation for Resolutions is mathematically given by

$d_x=-11-(-28sin49)$

$d_x=10.132m$

Where

$d_y=-11-(28cos49)$

$d_y=-29.37m$

Generally the equation for Direction is mathematically given by

$\theta=tan^{-1}(\frac{dx}{dy})$

$\theta=tan^{-1}(\frac{10.132}{29.37})$

$\theta=19.03 SE$