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givi [52]
3 years ago
9

A dog in an open field runs 11.0 m east and then 28.0 m in a direction 49.0 ∘ west of north. In what direction must the dog then

run to end up 11.0 m south of her original starting point?
Physics
1 answer:
Ede4ka [16]3 years ago
7 0

Answer:

\theta=19.03 SE

Explanation:

From the question we are told that:

d_1=11.0m East

d_2=28.0m 49 \textdegree west\ north

d_3=10m south

Generally the equation for Resolutions is mathematically given by

d_x=-11-(-28sin49)

d_x=10.132m

Where

d_y=-11-(28cos49)

d_y=-29.37m

Generally the equation for Direction is mathematically given by

\theta=tan^{-1}(\frac{dx}{dy})

\theta=tan^{-1}(\frac{10.132}{29.37})

\theta=19.03 SE

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