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4 years ago

Simplify the expression (1/4ab)^-2. Assume .

Mathematics

2 answers:

Greeley [361]4 years ago

3 0

<span>The Answer is (4ab)^2 or 16a^2b^2</span>

tester [92]4 years ago

3 0

Hi,

here's the answer!

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I’m factoring trinomials please help

Mila [183]

Answer:

I'll text you so I can help you for sure

6 0

3 years ago

Find the volume of the tetrahedron in the first octant bounded by the coordinate planes and the plane passing through (2 comma 0

SVETLANKA909090 [29]

Answer:

The volume of the tetrahedron is:

$\frac{50}{3}=16.667$

Step-by-step explanation:

The volume of the tetrahedron is given by the intersection of the planes x = 0, y = 0, z = 0 and the plane formed by the three points given.

The equation of the plane formed by the three points is:

Points: (2,0,0);(0,5,0);(0,0,4)

$\pi :\frac{x}{2} +\frac{y}{5} +\frac{z}{4} =1$

It can also be expressed as:

$10x + 4y+5z=20$

We have to calculate the triple integral, therefore we must define the domain:

The values of x are given by:

0≤x≤2

We will integrate the values of y between the y = 0 axis and the line formed when z = 0:

z=0 ⇒ 10x + 4y=2 ⇒ $y=\frac{20-10x}{4} =$

$0\leq y \leq 5-\frac{5}{2}x$

We will integrate the values of z between the plane z = 0 and the plane 10x + 4y+5z=20

10x + 4y+5z=20 ⇒ $z=\frac{20-10x-4y}{5} =4-2x-\frac{4}{5}y$

$0\leq z \leq 4-2x-\frac{4}{5}y$

The volume of the tetrahedron is:

$\int\limits^{2}_{0} \ \ \ \int\limits^{5-\frac{5}{2} x}_{0} \ \ \ \int\limits^{4-2x-\frac{4}{5}y }_{0} {z} \, dz\, dy \,dx$

$\int\limits^{2}_{0} \ \ \ \int\limits^{5-\frac{5}{2} x}_{0} \frac{z^2}{2}|^{4-2x-\frac{4}{5}y}_0\, dy \,dx$

$\frac{z^2}{2}|^{z=4-2x-\frac{4}{5}y}_{z=0}=\frac{5}{25}(5x+2(y-5))^2$

$\int\limits^{2}_{0} \ \ \ \int\limits^{5-\frac{5}{2} x}_{0} {\frac{5}{25}(5x+2(y-5))^2}\, dy \,dx$

$\int\limits^{2}_{0} {-\frac{25}{6}(x-2)^3} dx=-\frac{25}{24} (x-2)^4|^{2}_{0}=\frac{50}{3}$

6 0

4 years ago

Simplify- 5+2{3x+7(2-x)}

oksano4ka [1.4K]

Answer:

16x+19

Step-by-step explanation:

i might be wrong and its gonna take so long to explain it

4 0

3 years ago

Given the rectangular solid, RS = 6, ST = 3, and SL = 4. Solve for KT.

katrin [286]

First thing is that you need to find the diagonal of the rectangle

but remember is it a horizontal rectangle.

So let's start it :)

d= √6²+3²

d= √36+9

d= √54

d= 6.7082

But wait.. we are not done yet

We need to solve KT

we have 6.7082 which is the base and we have SL=4 which is the height

so with this 2 information we can find KT

KT is the hypotenuse because when you draw the line from K to T you'll see that it is the longest line.

Use the hypotenuse formula which is

C = √a²+b²

Now replace C by KT since we are solving for KT instead of C. Got it ?:)

KT= √6.7080²+4²

KT= 7.81

I do it with decimals so it might be little bit confusing to you but I think you can solve that different ways :)

Well I hope that's help and if not I am so sorry.

7 0

3 years ago

Read 2 more answers

I really need help with Algebra Asp!!!

mario62 [17]

⚓Hola User______________

⚓Here is Your Answer...!!!

_____________________

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↪In the GIVEN graphs , both are of same parabola , only they are translated one upon another ,...

↪thus the Option C)

↪THE GRAPH OF Y= x^2 +1 IS THE GRAPH OF y= x^2 +4 TRANSLATED THREE UNITS DOWN

5 0

3 years ago