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3 years ago

Which is the value of this expression when a = 5 and k = negative 2?

Mathematics

1 answer:

LuckyWell [14K]3 years ago

6 0

Answer:

Step-by-step explanation:

hello :

this expression equivalent to : (3/a)^5

because ;3²a^(-2)/3a^(-1)= (3²/3)×(a^(-2)/a^(-1)) = 3a^(-2+1) = 3a^(-1) = 3/a

now : a=5 and k= -2 so : (3/5)^(-2) = (5/3)² =25/9

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Step-by-step explanation:

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3 years ago

5g + 7g and g(5 + 7) when g=6

oksian1 [2.3K]

Answer:

Value of equation = 144

Step-by-step explanation:

Given:

5g + 7g + g(5 + 7)

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Find:

Value of equation

Computation:

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3 years ago

Applying properties of Exponents In Exercise, use the properties of exponents to simplify the expression.

eimsori [14]

Answer:

(a) $5^{8}$

(b) 3

(d) $\dfrac{1}{6}$

Step-by-step explanation:

We need simplify the given expressions.

(a)

Consider the given expression is

$(5^4)(25^2)$

$(5^4)((5^2)^2)$

Using the properties of exponents we get

$(5^4)(5^4)$ $[\because (a^m)^n=a^{mn}]$

$5^{4+4}$ $[\because a^ma^n=a^{m+n}]$

$5^{8}$

(b)

Consider the given expression is

$(9^{\frac{1}{3}})(3^{\frac{1}{3}})$

$((3^2)^{\frac{1}{3}})(3^{\frac{1}{3}})$

Using the properties of exponents we get

$(3^{\frac{2}{3}})(3^{\frac{1}{3}})$ $[\because (a^m)^n=a^{mn}]$

$3^{\frac{2}{3}+\frac{1}{3}}$ $[\because a^ma^n=a^{m+n}]$

$3^{1}$

$3$

(c)

Consider the given expression is

$(\dfrac{1}{3})^{-3}$

Using the properties of exponents we get

$(\dfrac{3}{1})^{3}$ $[\because a^{-n}=\dfrac{1}{a^n}]$

$3^{3}$

$27$

(d)

Consider the given expression is

$(6^4)(6^{-5})$

Using the properties of exponents we get

$6^{4+(-5)}$ $[\because a^ma^n=a^{m+n}]$

$6^{-1}$

$\dfrac{1}{6^{1}}$ $[\because a^{-n}=\dfrac{1}{a^n}]$

$\dfrac{1}{6}$

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Answer:

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Step-by-step explanation:

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