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Marta_Voda [28]
3 years ago
8

The chemical equation for the formation of ammonia is unbalanced.

Chemistry
1 answer:
ratelena [41]3 years ago
7 0
Balance Chemical equation is as follow,

<span>                           3 H</span>₂ <span>(g) + N</span>₂ <span>(g)    </span>→<span>    2 NH</span>₃ <span>(g)

According to balanced equation, 3 Molecules (3 moles) of Hydrogen reacts with 1 Molecule of N</span>₂ to produce 2 moles (2 Molecules) of NH₃.

Result:
          2 Molecules of Ammonia are produced by reacting 3 molecules of Hydrogen and 1 molecule of Nitrogen.
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3 years ago
Four molecules have carbon as the central atom and hydrogen atoms around it. Which shape would give rise to a polar molecule?
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Four molecules have carbon as the central atom and hydrogen atoms around it. The shape that would give rise to a polar molecule is a bent shape. <span>The bent shape will not be symmetrical which will result to being polar. Hope this answers the question.</span>
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2 years ago
In their notebook you see that it takes 9 hours for a sixth of a 0.5M solution of BC2 to react. Unfortunately, you have somewher
trasher [3.6K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The concentration of BC_2 that should used originally is C_Z_o = 0.4492M

Explanation:

     From the question we are told that

         The necessary elementary step is  

                  2BC_2 ----->4C + B_2

          The  time taken for sixth of 0.5 M of reactant to react t = 9 hr

           The time available is t_a = 3.5 hr

             The desired concentration to  remain C  = 0.42M

Let Z be the reactant ,   Y be the first product and X the second product

Generally the elementary rate  law is mathematically as

                    -r_Z = kC_Z^2 = - \frac{d C_Z}{dt}

Where k is the rate constant ,  C_Z is the concentration of Z

From the elementary rate law we see that the reaction is second order (This because the concentration of the reactant is raised to power 2 )

 For second  order reaction

            \frac{1}{C_Z}  - \frac{1}{C_Z_o}  = kt

Where C_Z_o is the initial concentration of Z which a value of   C_Z_o = 0.5M

       From the question we are told that it take  9 hours  for the concentration of  the reactant to become

                 C_Z =  C_Z_o - \frac{1}{6}  C_Z_o

                  C_Z = 0.5  - \frac{0.5}{6}

                       = 0.4167 M

So      

                     \frac{1}{0.4167}  - \frac{1}{0.50}  =  9 k

                          0.400 = 9 k

                =>    k = 0.044\  L/ mol \cdot hr^{-1}

  For   C_Z = 0.42M

                \frac{1}{0.42} - \frac{1}{C_Z_o}  = 3.5 * 0.044

                2.38 -  0.154  =    \frac{1}{C_Z_o}

                           2.226  =    \frac{1}{C_Z_o}

                            C_Z_o = \frac{1}{2.226}

                             C_Z_o = 0.4492M

                       

           

             

         

4 0
3 years ago
A piece of limestone erodes due to acid rain. This process can be best described as a...
scZoUnD [109]
A. Slow Chemical Change
4 0
3 years ago
Read 2 more answers
Can somebody help me with these 2 things. I honestly just need the acids and bases for both
pochemuha

Answer:

The Bronsted-Lowery acid is H2O

The Bronsted-Lowery base is CO3

The conjugate acid is HCO3

The conjugate base is OH

Explanation:

Molocules that lose a hydrogen in a reaction act as an acid, and those that recieve one act as a base.

8 0
3 years ago
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