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Marta_Voda [28]

3 years ago

8

The chemical equation for the formation of ammonia is unbalanced.

1 answer:

ratelena [41]3 years ago

7 0

Balance Chemical equation is as follow,

<span> 3 H</span>₂ <span>(g) + N</span>₂ <span>(g) </span>→<span> 2 NH</span>₃ <span>(g)

According to balanced equation, 3 Molecules (3 moles) of Hydrogen reacts with 1 Molecule of N</span>₂ to produce 2 moles (2 Molecules) of NH₃.

Result:
2 Molecules of Ammonia are produced by reacting 3 molecules of Hydrogen and 1 molecule of Nitrogen.

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WILL MARK YOU THE BRAINLIEST IF YOU ANSWER THESE TWO QUESTION CORRECTLY :)

lara [203]

Answer: 1. HYDROCARBONS? 2. ALKANES?

i'm not exactly AMAZING at this but i did some research and this is what i think it is i'm also not in this grade but i tried.

7 0

3 years ago

Four molecules have carbon as the central atom and hydrogen atoms around it. Which shape would give rise to a polar molecule?

zzz [600]

Four molecules have carbon as the central atom and hydrogen atoms around it. The shape that would give rise to a polar molecule is a bent shape. <span>The bent shape will not be symmetrical which will result to being polar. Hope this answers the question.</span>

7 0

2 years ago

In their notebook you see that it takes 9 hours for a sixth of a 0.5M solution of BC2 to react. Unfortunately, you have somewher

trasher [3.6K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The concentration of $BC_2$ that should used originally is $C_Z_o = 0.4492M$

Explanation:

From the question we are told that

The necessary elementary step is

$2BC_2 ----->4C + B_2$

The time taken for sixth of 0.5 M of reactant to react $t = 9 hr$

The time available is $t_a = 3.5 hr$

The desired concentration to remain $C = 0.42M$

Let Z be the reactant , Y be the first product and X the second product

Generally the elementary rate law is mathematically as

$-r_Z = kC_Z^2 = - \frac{d C_Z}{dt}$

Where k is the rate constant , $C_Z$ is the concentration of Z

From the elementary rate law we see that the reaction is second order (This because the concentration of the reactant is raised to power 2 )

For second order reaction

$\frac{1}{C_Z} - \frac{1}{C_Z_o} = kt$

Where $C_Z_o$ is the initial concentration of Z which a value of $C_Z_o = 0.5M$

From the question we are told that it take 9 hours for the concentration of the reactant to become

$C_Z = C_Z_o - \frac{1}{6} C_Z_o$

$C_Z = 0.5 - \frac{0.5}{6}$

$= 0.4167 M$

So

$\frac{1}{0.4167} - \frac{1}{0.50} = 9 k$

$0.400 = 9 k$

=> $k = 0.044\ L/ mol \cdot hr^{-1}$

For $C_Z = 0.42M$

$\frac{1}{0.42} - \frac{1}{C_Z_o} = 3.5 * 0.044$

$2.38 - 0.154 = \frac{1}{C_Z_o}$

$2.226 = \frac{1}{C_Z_o}$

$C_Z_o = \frac{1}{2.226}$

$C_Z_o = 0.4492M$

4 0

3 years ago

A piece of limestone erodes due to acid rain. This process can be best described as a...

scZoUnD [109]

A. Slow Chemical Change

4 0

3 years ago

Read 2 more answers

Can somebody help me with these 2 things. I honestly just need the acids and bases for both

pochemuha

Answer:

The Bronsted-Lowery acid is H2O

The Bronsted-Lowery base is CO3

The conjugate acid is HCO3

The conjugate base is OH

Explanation:

Molocules that lose a hydrogen in a reaction act as an acid, and those that recieve one act as a base.

8 0

3 years ago