Answer:
Moles of NaCl formed is 6.0 moles
Explanation:
We are given the equation;
2 Na(s) + Cl₂(g) → 2 NaCl(s)
- Moles of Na is 6.0 moles
- Moles of Cl₂ is 4.0 moles
From the reaction;
2 moles of sodium reacts with 1 mole of chlorine gas to form 2 moles of NaCl
In this case;
6 moles of Na would require 3 moles of Cl₂, this means that chlorine gas is in excess.
Thus, the rate limiting reagent is sodium.
But, 2 moles of sodium reacts to form 2 moles of NaCl
Therefore;
Moles of NaCl = Moles of Na
= 6.0 moles
Thus, moles of sodium chloride produced is 6.0 moles
Answer:
166,600J
Explanation:
Kinetic energy (K.E), which is the energy due to motion of a body, can be calculated by using the formula;
K.E = 1/2 × m × v²
Where;
K.E = kinetic energy (joules)
m = mass of body (kg)
v = speed or velocity (m/s)
According to this question, the mass of the roller coaster is 833.0 kg while its velocity/speed is 20.0m/s.
K.E = 1/2 × 833 × 20²
K.E = 1/2 × 833 × 400
K.E = 1/2 × 333200
K.E = 166,600
Therefore, the kinetic energy of the roller coaster car is 166,600J.
Answer:
-138.9 kJ/mol
Explanation:
Step 1: Convert 235.8°C to the Kelvin scale
We will use the following expression.
K = °C + 273.15 = 235.8°C + 273.15 = 509.0 K
Step 2: Calculate the standard enthalpy of reaction (ΔH°)
We will use the following expression.
ΔG° = ΔH° - T.ΔS°
ΔH° = ΔG° / T.ΔS°
ΔH° = (-936.92kJ/mol) / 509.0K × 0.51379 kJ/mol.K
ΔH° = -3.583 kJ (for 1 mole of balanced reaction)
Step 3: Convert -9.9°C to the Kelvin scale
K = °C + 273.15 = -9.9°C + 273.15 = 263.3 K
Step 4: Calculate ΔG° at 263.3 K
ΔG° = ΔH° - T.ΔS°
ΔG° = -3.583 kJ/mol - 263.3 K × 0.51379 kJ/mol.K
ΔG° = -138.9 kJ/mol
Answer:
3,5-dimethyl-2-octene
Explanation:
When naming an organic molecule with a double bond, the chain has to include the double bond. This means that there are 8 carbon atoms on the central chain. The molecule is octene. The double bond is after the second carbon, making it 2-octene. You can't say that its 6-octene because you want to have the smallest number possible in front.
The molecules attached are two methyl groups. Since you have two methyl groups, the name will be dimethyl. Start counting from the side closest to the double bond. This gives you a 3, 5-dimethyl group.
