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Anton [14]
3 years ago
7

How is a molecule of hydrogen formed from two hydrogen atoms?

Chemistry
1 answer:
Shtirlitz [24]3 years ago
8 0
A molecule of hydrogen is formed by two hydrogen atoms, that is a fact.

How does it work? When two atoms, known as "diatomic" pair with another in a bond known non-polar covalent bonds. Where they equally share electrons. A Hydrogen atoms needs 1 more electrons to fill its first shell fully and have a full valence shell. So if two H's share their electrons, they'll both have a full V-Shell!

That's the basics of both the H-H bond and all the other diatomic bonds as well. 
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What is the most important alloy that we use in construction?
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Answer:

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Explanation:

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3 years ago
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What would be the pH of an H2SO4 solution if the [H+] = 4.58 x 10-5 moles/liter?
Ghella [55]

Answer: pH of an H_2SO_4 solution is 4.34

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

pH=-\log [H^+]

H_2SO_4\rightarrow 2H^++SO_4^{2-}

Putting in the values:

pH=-\log[4.58\times 10^{-5}]

pH=4.34

Thus pH of an H_2SO_4 solution if the [H^+] is 4.58\times 10^{-5}] is 4.34

4 0
3 years ago
What is the composition of 'Clean dry air'<br><br> - Idk what subject its just science
Luba_88 [7]
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7 0
3 years ago
The sum of pH and pOH for any aqueous solution equals .
Vsevolod [243]

Answer:

pH is calculated by taking negative logarithm of hydrogen ion concentration. Acids have pH ranging from 1 to 6.9, bases have pH ranging from 7.1 to 14 and neutral solutions have pH equal to 7. Thus the sum of pH and pOH is 14

Explanation:

6 0
3 years ago
Octane has a density of 0.703 g/ml. Calculate the mass of CO2(g) produced by burning one
STatiana [176]

The mass of CO₂ gas produced during the combustion of one gallon of octane is 8.21 kg.

The given parameters:

  • <em>Density of the octane, ρ = 0.703 g/ml</em>
  • <em>Volume of octane, v = 3.79 liters</em>

<em />

The mass of the octane burnt is calculated as follows;

m = \rho V\\\\m = 0.703 \ \frac{g}{ml} \times 3.79 \ L \ \frac{1000 \ ml}{L} \\\\m = 2,664.37 \ g

The combustion reaction of octane is given as;

2C_8H_{18} +  \ 25O_2 \ --> \ 16CO_2 \ + \ 18H_2O

From the reaction above:

228.46 g of octane -------------------> 704 g of  CO₂ gas

2,664.37 of octane --------------------> ? of CO₂ gas

= \frac{2,664.37 \times 704}{228.46} \\\\= 8,210.3 \ g\\\\= 8.21 \ kg

Thus, the mass of CO₂ gas produced during the combustion of one gallon of octane is 8.21 kg.

Learn more about combustion of organic compounds here: brainly.com/question/13272422

8 0
3 years ago
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