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anygoal [31]
3 years ago
7

A certain solution has [H3O+] = 8.1 X 10-8 M Calculate the pH of this solution

Chemistry
1 answer:
Aleonysh [2.5K]3 years ago
3 0

Answer:

pH = 7.092

Explanation:

pH is given by the formula;

pH = - log[H3O+]

Given [H3O+] = 8.1 X 10^-8 M

Therefore;

pH = -log 8.1 X 10^-8 M

     = 7.092

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3 years ago
calculate the ph for each case in the titration of 50.0 ml of 0.130 m hclo(aq) with 0.130 m koh(aq). use the ionization constant
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The ph before the addition of any Koh is<u> 10.105.</u>

Concentration is the abundance of a constituent divided by way of the overall volume of an aggregate. several sorts of mathematical descriptions may be outstanding: mass concentration, molar concentration, variety concentration, and extent awareness.

After the addition of 50 ml KOH,

moles of KOH = 50 * 0.13 =<u> 6.5 mmol </u>

<u>moles </u><u>of HClO = 50 * 0.13 = 6.5 mmol </u>

occurred hydrolysis solution,

pH = 0.5(14 + pKa + log [base conjugate])

pH = 0.5(14 + (- log (4 * 10^-8)) + log (6.5/(50 + 50)))

pH = <u>10.105</u>

The concentration of a substance is the quantity of solute found in a given amount of solution. Concentrations are normally expressed in terms of molarity, defined because of the variety of moles of solute in 1 L of answer.

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4 0
2 years ago
Determine the rate law, including the values of the orders and rate law constant, for the following reaction using the experimen
murzikaleks [220]

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Explanation in attached image

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3 years ago
Which statement supports one of Dalton's contributions to the atomic theory?
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<span>C) The element nitrogen is made up of carbon and nitrogen</span>
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3 years ago
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What is the molarity of a 250.0 ml aqueous solution of sodium hydroxide that contains 15.5 grams of solute?
Whitepunk [10]

The molar concentration of the solution is 1.55 mol/L.


1. Convert grams to moles.


\text{Moles of NaOH} = 15.5 \text{g NaOH} \times \frac{\text{1 mol NaOH}}{\text{40.00 g NaOH}} = \text{0.3875 mol NaOH}\\

2. Convert millilitres to litres


V = 250.0 \text{mL} \times \frac{\text{1 L}}{\text{1000 mL}} = \text{0.2500 L}\\

3. Calculate the molar concentration (c)


c = \frac{\text{moles}}{\text{litres}} = \frac{\text{0.2875 mol}}{\text{0.2500 L}} = \textbf{1.55 mol/L}



3 0
3 years ago
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