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Doss [256]
3 years ago
8

A lawnmower engine running for 20 minutes does 4560000 j of work. What is the power output of the engine

Physics
1 answer:
Alenkasestr [34]3 years ago
3 0

<em>Answer: </em>

tim e (t) = 20 min.

            = 20 × 60 = 1200 s ,

Work ( W) = 4560000 J

                 = 4560 KJ ,

Determine:

                 Power output (P) = Work ÷ time

                                              = 4560 ÷  1200

                                         <em>   P  = 3.8 KW</em>


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Here c  is the speed of light with the value  c =  3.08 *10^{8} \  m/s

=>     t =  \frac{3.311 *10^{17} }{3.08 *10^{8}}

=>     t =  1.075 *10^9 \ s

converting to years

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Now the total time taken is mathematically represented as

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3 years ago
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Centripetal force is equal to (mv^2)/r
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