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1 year ago

If the wavelength of light in the visible region is known, what is also known? check all that apply. question 4 options:

Physics

1 answer:

maw [93]1 year ago

7 0

If the wavelength of light in the visible region is known, it is also known as frequency.

<h3>What is frequency?</h3>

Recurrence is the quantity of events of a rehashing occasion for every unit of time. It is likewise once in a while alluded to as worldly recurrence to underline the differentiation to spatial recurrence, and customary recurrence to underscore the difference to rakish recurrence. Rotating current (ac) recurrence is the quantity of cycles each second in an air conditioner sine wave. Recurrence is the rate at which current heads in a different path each second. It is estimated in hertz (Hz), a global unit of measure where 1 hertz is equivalent to 1 cycle each second. It is likewise infrequently alluded to as transient recurrence to stress the difference to spatial recurrence, and normal recurrence to accentuate the differentiation to precise recurrence. Recurrence is estimated in hertz (Hz) which is equivalent to one occasion each second.

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A child slides down a hill on a toboggan with an acceleration of 1.8 m/s^2. If she starts at rest, how far has she traveled in :

DENIUS [597]

Explanation:

It is given that,

The acceleration of the toboggan, $a=1.8\ m/s^2$

Initial speed of the toboggan, u = 0

We need to find the distance covered by the toboggan. Using the second equation of motion as :

$s=ut+\dfrac{1}{2}at^2$

At t = 1 s

$s=\dfrac{1}{2}\times 1.8\times 1^2$

$s_1=0.9\ m$

At t = 2 s

$s=\dfrac{1}{2}\times 1.8\times 2^2$

$s_2=3.6\ m$

At t = 3 s

$s=\dfrac{1}{2}\times 1.8\times 3^2$

$s_3=8.1\ m$

Hence, this is the required solution.

4 0

3 years ago

Two forces F1 and F2 of equal magnitude are applied to a brick of mass 20kg lying on the floor as shown in the figure above. If

jeka57 [31]

Let $F_{1}=F_{2}=F$ .

Normal force equals (using Newton's third law) $N=mg+F\sin30^{o}-F\sin37^{o}$ .

$F_{f}\leq \mu N = \mu(mg+F\sin30^{o}-F\sin37^{o})$ , but $F_{f}\leq F(\cos30^o+\cos37^o)$ for all $F_{f}$ (in order to start moving the break). Therefore $F(\cos 30^o+\cos37^o)\geq \mu(mg+F\sin30^{o}-F\sin37^{o})$ , solving for $F$ : $F\geq \frac{\mu mg}{\cos30^o+\cos37^o-\mu\sin30^o+\mu\sin37^o}\approx 46,91\; \textbf{N}$

7 0

2 years ago

Doubling an object’s height will have what effect on its potential energy due to gravity?

timurjin [86]

Potential energy due to gravity = Ep = mgh [symbols have their usual meaning ]
Evidently, HALVING the mass will make Ep , HALF its previous value. So, It will be halved.

5 0

2 years ago

Read 2 more answers

This. please help me.

kramer

The transfer of heat from the Sun is in the form of thermal radiation (also called infrared radiation)
The transfer of heat at the person’s feet is by thermal conduction. During the day the sand will be hot so if you step on it with bare feet there will be conduction of heat to the feet.

3 0

2 years ago

A 65 N boy sits on a sled weighing 52 N on a horizontal surface. The coefficient of friction between the sled and the snow is 0.

pogonyaev

Answer:

1.40 N

Explanation:

The magnitude of the frictional force is given by:

$F=\mu N$

where

$\mu$ is the coefficient of friction

N is the magnitude of the normal reaction

The coefficient of friction for this problem is $\mu=0.012$ . The magnitude of the normal reaction is equal to the combined weight of the boy and the sled, because the surface is horizontal, so

$N=65 N+52 N=117 N$

Therefore, the frictional force is

$F=\mu N=(0.012)(117 N)=1.40 N$

3 0

3 years ago