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tia_tia [17]
1 year ago
8

If the wavelength of light in the visible region is known, what is also known? check all that apply. question 4 options:

Physics
1 answer:
maw [93]1 year ago
7 0

If the wavelength of light in the visible region is known, it is  also known as  frequency.

<h3>What is frequency?</h3>

Recurrence is the quantity of events of a rehashing occasion for every unit of time. It is likewise once in a while alluded to as worldly recurrence to underline the differentiation to spatial recurrence, and customary recurrence to underscore the difference to rakish recurrence. Rotating current (ac) recurrence is the quantity of cycles each second in an air conditioner sine wave. Recurrence is the rate at which current heads in a different path each second. It is estimated in hertz (Hz), a global unit of measure where 1 hertz is equivalent to 1 cycle each second. It is likewise infrequently alluded to as transient recurrence to stress the difference to spatial recurrence, and normal recurrence to accentuate the differentiation to precise recurrence. Recurrence is estimated in hertz (Hz) which is equivalent to one occasion each second.

Learn more about frequency, visit

brainly.com/question/12833229

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emmasim [6.3K]

Answer:

The World Series

Explanation:

The Super Bowl is the championship American Football game, and the World Cup is the Soccer/Football game.

American Football and Football are different things. The first is what Americans call football, while the other is what Americans call soccer. It is confusing.

6 0
3 years ago
A 7.7 kg sphere makes a perfectly inelastic collision with a second sphere initially at rest. The composite system moves with a
klemol [59]

Answer:

15.4 kg.

Explanation:

From the law of conservation of momentum,

Total momentum before collision = Total momentum after collision

mu+m'u' = V(m+m').................... Equation 1

Where m = mass of the first sphere, m' = mass of the second sphere, u = initial velocity of the first sphere, u' = initial velocity of the second sphere, V = common velocity of both sphere.

Given: m = 7.7 kg, u' = 0 m/s (at rest)

Let: u = x m/s, and V = 1/3x m/s

Substitute into equation 1

7.7(x)+m'(0) = 1/3x(7.7+m')

7.7x = 1/3x(7.7+m')

7.7 = 1/3(7.7+m')

23.1 = 7.7+m'

m' = 23.1-7.7

m' = 15.4 kg.

Hence the mass of the second sphere = 15.4 kg

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I hope this helps!

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