What type of electromagnetic radiation is being used in the picture?

Fill in the blanks to the statement below in the next three questions: A train composed of a small engine car and a massive carg

Assoli18 [71]

Answer:

1) is equal to, 2) is equal to, connected and moving along the same track.

Explanation:

1) The speed of the small engine car is equal to the speed of the massive cargo car.

2) The magnitude of the acceleration of the small engine car is equal to the magnitude of the acceleration of massive cargo car because they are connected and moving along the same track.

3 0

4 years ago

A pump is used to lift 100 KG of water from a wel 60 m deep,in 20 S If force of gravity on 1 KG is 10 N,find

Harlamova29_29 [7]

Explanation:

Given,

m = 100 kg
g = 10 N/kg¹
h = 60 m
t = 20 s

To Find:

a) Work done by the pump

b) Potential energy stored in the water

c)Power spent by the pump

d)Power rating of the pump.

Solution:

a) Work done by the pump

We know that,

$\rm \: Work \: done = Force * Distance \: moved$

f = 100 kg * 10N/kg
d = 60 m

$\rm \: Work\; Done =(100 \: kg \times \cfrac{10N}{kg} ) \times 60 \: m$

$\rm \: Work\; Done =1000 \times 60 \: joule$

$\boxed{\rm \: Work\; Done =60000 \: joule}$

[The unit'll be joule since N×M = J]

b) Potential energy stored in the water

$\rm \: P.E = m \cdot g \cdot h$

m = 100 kg
g = 10N/kg
h = 60

$\rm \: P.E =100 \:kg \: \times \cfrac{10 \: N}{kg} \times 60$

$\boxed{\rm \: P.E =60000 \: joule}$

same condition here as well, N×M = J
c) Power of the Pump

$\rm \: P = W/T$

where P = Power; W = Work done & T = Time taken
As we got the value of work done on question (a),& ATQ time taken is 20 S.

$\rm \: P = \cfrac{60000 \: joule}{20 \: seconds} =\boxed{\rm { 3000 \: Watts }}\: or \: \boxed{\rm 3 \: kW}$

d) Power rating of the pump = 3 kW

Assumption: The pump is 100% efficient & works well.

6 0

2 years ago

a 10kg box car rolls at 6m/s and crashes into a 20kg box car that is at rest. After the crash, both cars are stuck together. wha

Goshia [24]

Answer:

Their velocity is 0m/s because the first box was only 10 kg and the second box was double the weight

5 0

3 years ago

A 45.0 - kg girl is standing on a 150. - kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is a

Mrac [35]

Answer:

The velocity relative to the surface of the ice is 6.5 m/s.

Explanation:

Given that,

Mass of girl m= 45.0 kg

Mass of plank M= 150 kg

Velocity = 1.50 m/s

We need to calculate the velocity relative to the surface of the ice

Using conservation of momentum

$mv_{1}+Mv_{2}=(m+M)v$

Here, $v_{2}=0$ because plank at rest

$v_{1}=\dfrac{m+M}{m}\times v$

Put the value into the formula

$v_{1}=\dfrac{45+150}{45}\times1.50$

$v_{1}=6.5\ m/s$

Hence, The velocity relative to the surface of the ice is 6.5 m/s.

6 0

3 years ago

What do scientists use to predict the location of electrons in atoms

Oksana_A [137]

scientists use the electron cloud model to predict the location of electrons in an atom

6 0

3 years ago

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