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3 years ago

What sentence(s) is/are true when we talk about equipotential lines?

Physics

1 answer:

rodikova [14]3 years ago

6 0

Answer:

a. True

Explanation:

Equipotential lines are the imaginary lines in the space where actually the electric potential is same at each and every point.

Work is not required to move along such points of the equipotential line because the movement is always perpendicular to the electric field lines because these lines are always perpendicular to the electric field lines.

The electric potential for a point charge is given mathematically as:

$V=\frac{1}{4\pi.\epsilon_0}\times \frac{Q}{r}$

where:

$Q=$ magnitude of the point charge

$r=$ radial distance form the charge

$\epsilon_0=$ permittivity of free space

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Sketch the electric field around these two objects if they have the same sign of charge. Make a separate drawing showing equipot

diamong [38]

Answer:

* far from one of the charges, the field of the other charge is small and can be neglected

* on the outside of the loads the fields are added territorially

* between the charges the two fields tend to vanish

Explanation:

The electric field around two objects with charge of the same sign, for simplicity suppose that the objects have positive point spherical charges,

E = k q / r2

bold letters indicate vectors, therefore the total electric field is

E_total = E1 + E2

the module of this field is

E_total = E1- E2

therefore we can outline this field

* far from one of the charges, the field of the other charge is small and can be neglected

* on the outside of the loads the fields are added territorially

* between the charges the two fields tend to vanish

An outline of these shows in Attachment A

The equipotential surfaces are defined as being perpendicular to the electric field lines since the electric field and the power difference are related

E = $\frac{dV}{dx} i^ + \frac{dV}{dy} j^ + \frac{dV}{dz} k^ = \Delta V$

We can schematize some characteristics of these surfaces

* very close to each load are spherical surfaces

* very far from the load is an elliptical surface, which envelops the loads

* between them there is a point of zero potential point C

See attached part B

5 0

3 years ago

When an electric drill is used to bore a hole into a wooden beam, the user notices that the drill bit gets very hot.

Bess [88]

Wood is a bad conductor of heat. The drilling process involve heat generation between the drill and the wooden material that can not be dissipated away easily. With deep drilling the drill may get so hot that the chips come out in a state of smoking coal.<span>
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7 0

3 years ago

Frictional force is____of area of contact

Elis [28]

Answer:

The force due to friction is generally independent of the contact area between the two surfaces. This means that even if you have two heavy objects of the same mass, where one is half as long and twice as high as the other one, they still experience the same frictional force when you drag them over the ground.

Explanation:

Independent

8 0

2 years ago

) determine the density of a 32.5 g metal sample that displaces 8.39 ml of water.

sweet-ann [11.9K]

Density is the ratio of a substance's mass to its volume. On the other hand, according to Archimedes' principle, the volume of water displaced is equal to the volume of the object placed on the water. Thus, the density of the metal is equal to 8.39 mL. So, the density would be

Density = 32.5 g/8.39 mL = 3.87 g/mL

3 0

3 years ago

Read 2 more answers

regrine falcons frequently grab prey birds from the air. Sometimes they strike at high enough speeds that the force of the impac

solmaris [256]

Answers:

a) 30 m/s

b) 480 N

Explanation:

The rest of the question is written below:

a. What is the final speed of the falcon and pigeon?

b. What is the average force on the pigeon during the impact?

<h3>a) Final speed</h3>

This part can be solved by the Conservation of linear momentum principle, which establishes the initial momentum $p_{i}$ before the collision must be equal to the final momentum $p_{f}$ after the collision: