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gayaneshka [121]
3 years ago
9

Equation for the line that is perpendicular to the line 4y=5x-8 through the point (-5,4)

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
8 0

To find the equation for this line, we are going to use point-slope form. First, to find the perpendicular slope, we need to find the slope of the line 4y=5x - 8. To do this, we must transform this equation into slope-intercept form so we can determine the slope.

4y=5x-8

We should divide both sides of the equation by 4 to put the equation into slope-intercept form.

4y/4 = 5x/4 - 8/4

y = 5/4x - 2

Therefore, we can determine that the slope of this equation is 5/4. The slope of the line perpendicular to this line has the opposite reciprocal slope. To find the opposite reciprocal of 5/4, we must make it negative and switch the numerator and the denominator. The opposite reciprocal of 5/4 is -4/5.

Now, we must use this slope and the point we were given, (-5, 4), to write a new equation.

y = m(x-h) + k

y = -4/5(x + 5) + 4

y = -4/5x - 4 + 4

y = -4/5x

Therefore, your answer is y = -4/5x.

Hope this helps!

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