If 6 goes to 12, if it remains proportional, it should be x2. So 8 x 2 = 16. X = 16
Find Lim f(x) as x->0
for
f(x)=5x-8 ......x<0
f(x)=|-4-x|......x ≥ 0
Clearly
f(0)=|-4-0|=|-4|=4 exists.
The left-hand limit, as x-> 0- is f(0-)=5(0)-8=-8
The right hand limit, as x->0+ is f(0+)=|-4-0|=|-4|=4
Since the left and right limits do not both equal f(0), the limit does not exist.
Answer:
x = 60°
Step-by-step explanation:
let the missing angle be = x
Cos x = 8/16
x = Cos-¹ 0.5
x = 60°