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Lelechka [254]
3 years ago
12

Solve x:12 : x = 8:6 plase help this means a lot to me

Mathematics
1 answer:
kondor19780726 [428]3 years ago
5 0
If 6 goes to 12, if it remains proportional, it should be x2. So 8 x 2 = 16. X = 16
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Find slope of (-3,3)(2,1)
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Y-y1 /x-x1.

3-1/-3-2

2 /-5
-2/5
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4 years ago
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(18x^5+6x^4-12x^3)÷6x^2
statuscvo [17]
(3x^3 + x^2 - 2x)
when dividing exponents, subtract the exponents.
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6 0
4 years ago
2. Find the base of a triangle which has an area of 2 1/4 square inches, and a height of 1/8 in. ​
Maslowich

Answer:

36 inches

Step-by-step explanation:

Given data

Area of triangle =2 1/4 square inches

Area =9/4 square inches

Height of triangle =1/8 inches

We know that the expression for the area of triangle is

Area = 1/2Base *Height

9/4=1/2*Base *1/8

9/4=Base/16

Cross multiply

16*9=Base*4

144=Base*4

Base =144/4

Base=36 inches

7 0
3 years ago
No dia 15/05/2020 as 18h e 40min o G1 divulgou que a Paraíba tem 3.739 casos confirmados e 170 mortes por coronavírus. Qual a po
Andru [333]

Answer:

4.55%

Step-by-step explanation:

To find the percentage of deaths in relation to the number of cases confirmed, we just need to divide the number of deaths by the number of cases confirmed.

So we have that:

Percentage = Deaths / Cases

Percentage = 170 / 3739

Percentage = 0.0455 = 4.55%

The percentage of deaths in relation to the number of cases is 4.55%

5 0
3 years ago
The​ half-life of a certain tranquilizer in the bloodstream is 22 hours. How long will it take for the drug to decay to 90​% of
nasty-shy [4]

Answer:

It will take approximately 3.34 hours for the drug to decay to 90% of the original dosage

Step-by-step explanation:

As suggested, we use the formula for exponential decay:

A(t)=A_0\,e^{-k\,t}

From the given information, the half life of the drug in blood id 22 hours, so that means that it takes that number of hours to go from the initial value A_0, to a final value equal to A_0/2. Using this information we can find the decay rate "k" by solving for this parameter in the formula, and using the natural log function to bring the exponent down:

A(t)=A_0\,e^{-k\,t}\\\frac{A_0}{2} =A_0\,e^{-k\,*22}\\\frac{A_0}{A_0*2} =e^{-k\,*22}\\\frac{1}{2} =e^{-k\,*22}\\ln(\frac{1}{2})=-k\,*22\\ k=-\frac{ln(\frac{1}{2})}{22} \\k=0.0315

Now we use this value for the decay rate "k" to calculate how long it would take to decay to 90% of the original dose;

A(t)=A_0\,e^{-0.0315\,t}\\0.9*A_0} =A_0\,e^{-0.0315\,t}\\\frac{0.9*A_0}{A_0} =e^{-0.0315\,t}\\0.9 =e^{-0.0315\,t}\\ln(0.9)=-0.0315\,t\\ t=-\frac{ln(0.9)}{0.0315} \\t=3.3447\,hours

7 0
3 years ago
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