All categories

3 years ago

A cat requires a 3 mL injection of a 0.5% solution. How many milligrams will it receive per injection?

Mathematics

2 answers:

Kay [80]3 years ago

7 0

<h2>Hello!</h2>

The answer is: 15mg

0.5% means that there are 0.5 grams per 100 mL, and a 0.5 grams are equal to 500 milligrams.

So, to calculate how many milligrams will be received per injection, we need to make the following calculations:

$3mL*\frac{500mg}{100mL}=15mg$

Have a nice day!

zlopas [31]3 years ago

4 0

<h2>Answer:</h2>

<u>The answer is</u><u> 15mg</u>

<h2>Step-by-step explanation:</h2>

As we know that

The percentage can be written as

0.5 % solution means 0.5 / 100 = 0.005

Now 0.5 grams are equal to 500 milligrams.

So if we want to find percentage in 3mL we will write as

= 3 x (500 mg / 100 mL)

= 15 mg

You might be interested in

Graph the line with slope −1/2 and y-intercept −5.

Allushta [10]

First, we can write the equation of the line using the information provided:

$\begin{gathered} y=mx+b \\ where: \\ m=slope=-\frac{1}{2} \\ b=y-intercept=-5 \\ so: \\ y=-\frac{1}{2}x-5 \end{gathered}$

Now, we can create a table:

Finally, we can graph the line:

5 0

1 year ago

Explain how you can use equivalent fractions to find the quotient of 2 3 ÷ 4. Sample Response: Find a fraction that is equivalen

xz_007 [3.2K]

Answeno

Step-by-step explanation:

sorry

8 0

2 years ago

QRST is a parallelogram. Find x and y.

Wewaii [24]

In parallelograms, opposite sides are congruent, meaning that they are the same lengths. So, we have:

y - 4x = 9

-x + 4 = y

Add x to both sides of the second equation:

y + x = 4

y - 4x = 9

This is a system of linear equations. Solve by eliminating the y and subtracting the two equations:

5x = -5

x = -1

Use x to solve for y:

y + (-1) = 4

y = 5

So, x = -1 and y = 5.

5 0

3 years ago

Which point keeps the set of ordered pairs a function {(1,-2).(-2,4), (5,0)}

tester [92]

B (2,1) is the answer

4 0

3 years ago

How do you do this and what’s the answer to this I been stuck on this question for litterly 20 mins

Vsevolod [243]

$\bf T=2\pi \sqrt{\cfrac{L}{g}}\implies \stackrel{\textit{squaring both sides}}{(T)^2=\left( 2\pi \sqrt{\cfrac{L}{g}}\ \right)^2}\implies T^2=2^2\pi^2\sqrt{\left( \cfrac{L}{g} \right)^2} \\\\\\ T^2=4\pi^2\cfrac{L}{g}\implies T^2=\cfrac{4\pi^2L}{g}\implies gT^2=4\pi^2L\implies g=\cfrac{4\pi^2L}{T^2}$

6 0

3 years ago