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Anit [1.1K]
3 years ago
9

Does rapidly cooled rock contain small crystals?

Chemistry
1 answer:
Lisa [10]3 years ago
3 0
I believe they do, yes.
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a race car at the Daytona 500 zips around the track .its travel the first 80 kilometers in 0.4 hours. the next 114 kilometers ta
Ratling [72]
The answer to this should be around 40
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What's the element from this electron configuration?<br><br> 1s22s22p63s23p4
garri49 [273]
Sulfur would be the answer
7 0
3 years ago
Name the element described in each of the following:
musickatia [10]

Period  4  transition  element  that  forms  2+  ion  with  a  half‐filled  d  sub level  is
Manganese  (Mn)

What is the half-filled d sub-level?

Transition metals are an interesting and challenging group of elements.  They have perplexing patterns of electron distribution that don’t always follow the electron-filling rules.  Predicting how they will form ions is also not always obvious.

Transition metals belong to the d block, meaning that the d sublevel of electrons is in the process of being filled with up to ten electrons.  Many transition metals cannot lose enough electrons to attain a noble-gas electron configuration.  In addition,  the majority of transition metals are capable of adopting ions with different charges.  Iron, which forms either the Fe2+ or Fe3+ ions, loses electrons as shown below.

Some transition metals that have relatively few d electrons may attain a noble-gas electron configuration.  Scandium is an example. Others may attain configurations with a full d sublevel, such as zinc and copper.

to know more about  half-filled d sub-level

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6 0
2 years ago
what is the structure of XeO2F2???i know its hybridization as sp3d but cannot quite understand its diagram in free space,help an
skelet666 [1.2K]
The shape of XeO₂F₂ is Trigonal bi-pyramidal see-saw tetrahedron (see attached pictures)
- As you said the hybridization of Xe here is sp³d so its geometry has to be Trigonal bi-pyramidal in which F atom located on axial positions but for the final shape we exclude lone pair on Xe to give see-saw shape (see second picture) 
- Remember that we have 5 pairs (4 bond pairs + 1 lone pair) and we have to place lone pair at equatorial position.

6 0
3 years ago
Calculate the energy required to heat 566.0mg of graphite from 5.2°C to 23.2°C. Assume the specific heat capacity of graphite un
maw [93]

Answer:

7.23 J

Explanation:

Step 1: Given data

  • Mass of graphite (m): 566.0 mg
  • Initial temperature: 5.2 °C
  • Final temperature: 23.2 °C
  • Specific heat capacity of graphite (c): 0.710J·g⁻¹K⁻¹

Step 2: Calculate the energy required (Q)

We will use the following expression.

Q = c × m × ΔT

Q = 0.710J·g⁻¹K⁻¹ × 0.5660 g × (23.2°C-5.2°C)

Q = 7.23 J

6 0
3 years ago
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