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3 years ago

How does temperature change in the troposphere differ from the stratosphere?

1 answer:

5 0

In this region the air actually warms with height. Ozone is concentrated in this part of the atmosphere and it absorbs ultraviolet light from the Sun. More light is absorbed at higher altitudes compared to the lower stratosphere, so the temperature increases. In simple language, think of it as a strainer.

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Which observation illustrates the law of conservation of mass?

ludmilkaskok [199]

I think the correct answer among the choices listed above is the second option. The observation which illustrates the law of conservation of mass is that wh<span>en 3 g of carbon reacts with 8 g of oxygen, 11 g of carbon dioxide is produced. Other choices doesn't shows that mass in is equal to the mass out.</span>

7 0

4 years ago

¿Cuál es la densidad en g / mL de un material, si 30mL tienen una masa de 6 Kg?

blsea [12.9K]

Hola!

La densidad es una magnitud intensiva, es decir, no depende de la cantidad de material. La densidad se define como la relación entre la masa y el volumen de un cierto material y comúnmente se expresa en g/mL. A partir de esta definición podemos concluir que para hallar la densidad de un material es necesario conocer su masa y su volumen para posteriormente aplicar la ecuación tal como se describe a continuación:

$densidad= \frac{masa}{volumen}= \frac{6 kg}{30mL}* \frac{1000g}{1kg}=200g/mL$

Entonces, la opción correcta es la C. 200 g/mL

Saludos!

8 0

4 years ago

Is air an element, compound or mixture? explain your answer

emmainna [20.7K]

It is a mixture because the compounds that make up air e.g. oxygen (o2), Carbon dioxide (co2) and the most important Nitrogen which is an element and makes up 78.09% of air are not chemically bound in the way that compounds are because they can be separated easily and there has been no change in state to any of the compounds or elements in air!hope this helpful!

3 0

4 years ago

Read 2 more answers

Determine the Eo for a Cu-Pb Voltaic Cell

blagie [28]

Answer:

The standard cell potential (E₀) for a Cu-Pb voltaic cell is +0.215V

The experiment is used to determine the standard electrode potential of the Cu-Pb Voltaic cell.

Explanation:

A Voltaic cell is one in which electric energy is produced as a result of the difference in electric potential between two electrodes in chemical solutions that are usually connected by a salt bridge.

In a voltaic cell, the anode electrode is where oxidation (loss of electrons) occurs while reduction (gain of electrons) occurs at the cathode electrode.

The standard cell potential (E₀) is the difference between the potential of the cathode and anode at standard conditions, that is, at standard temperature, pressure and concentration.

It is usually expressed as

E₀ = E₀cell (cathode) - E₀cell (anode)

From the given question, the half cell equations are :

Cu(s) - 2e ⇒ Cu²⁺. with oxidation reaction occuring at the anode

Pb²⁺ + 2e ⇒ Pb (s). with reduction reaction occuring at the cathode

Meaning that the solid copper electrode is oxidised by losing two electrons which are gained by the Pb²⁺ ions which are subsequently reduced to solid lead at the other electrode.

Each half cell reaction has a standard electric potential (recall that the standard electric potential is the potential at standard conditions, that is, at standard temperature, pressure and concentrations.

)

The overall voltaic cell equation is given as:

Cu(s) I Cu²⁺(aq) II Pb²⁺ (aq) I Pb(s)

The standard cell potential E₀ is obtained by

E₀ = E₀cell (cathode) - E₀cell (anode)

At standard conditions, E₀ (Cu(s) ⇒ Cu²⁺ + 2e) = - 0.340V

E₀ (Pb²⁺ + 2e ⇒ Pb(s) = - 0.125V

Therefore, the standard cell potential for a Cu-Pb voltaic cell is,

E₀ = -0.125V - (-0.340V)

= -0.125V + 0.340V

= +0.215V

4 0

3 years ago

Calculate the quantity of electricity obtained from 2 moles of electrons

Vinil7 [7]

The quantity of electricity : 2 Faraday = 193000 Coulomb

<h3>Further explanation</h3>

Given

2 moles of electrons

Required

The quantity of electricity

Solution

According to Faraday, the amount of current flowing in the electrolysis cell is closely related to the amount of substance that reacts

1 Faraday is the amount of electricity that is passed in the electrolysis cell to obtain 1 mole of electrons. 1 mole of electrons is equivalent to an electric charge of 96500 Coulombs.

The conversion / relationship can be stated as follows:

1 Faraday = 1 mole of electrons = 96500 Coulombs

1 faraday = coulomb / 96500

Can be formulated

Coulomb = Q = I. t so:

$\large {\boxed {\bold {1 \: Faraday \: = \: \dfrac {i \: x \: t} {96500}}}}$

so for 2 moles electrons :

= 2 x 96500 C

= 193000 C

= 2 Faraday

6 0

3 years ago