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Mnenie [13.5K]
4 years ago
15

A green laser pointer emits light with a wavelength of 542 nm. What is the frequency of this light?

Chemistry
1 answer:
ehidna [41]4 years ago
6 0
As we know that wavelength and frequency is inversely proportional to each other. Greater the wavelength smaller the frequency and vice versa.
 
Solution:


The relation between wavelength and frequency is as follow,

υ = c / λ

where
            υ = frequency = ?
            c = velocity of light = 3.0 × 10⁸ ms⁻¹
            λ = wavenumber = 542 nm = 542 × 10⁻⁹ m
Putting the given values,
    
            υ = 3.0 × 10⁸ ms⁻¹ / 542 × 10⁻⁹ m
Result:
            υ = 5.53 × 10¹⁴ s⁻¹
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Read 2 more answers
A sample of 28 Mg decays initially at a rate of 53500 disintegrations per minute, but the decay rate falls to 10980 disintegrati
prisoha [69]

Answer : The half life of 28-Mg in hours is, 6.94

Explanation :

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by:

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant

t = time passed by the sample = 48.0 hr

a = initial amount of the reactant disintegrate = 53500

a - x = amount left after decay process disintegrate = 53500 - 10980 = 42520

Now put all the given values in above equation, we get

k=\frac{2.303}{48.0}\log\frac{53500}{42520}

k=9.98\times 10^{-2}hr^{-1}

Now we have to calculate the half-life.

k=\frac{0.693}{t_{1/2}}

9.98\times 10^{-2}=\frac{0.693}{t_{1/2}}

t_{1/2}=6.94hr

Therefore, the half life of 28-Mg in hours is, 6.94

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3 years ago
(((NEED ANSWER QUICK!!!)))<br><br> Which is the stronger conjugate base, CN- or OCN-? Explain
Shkiper50 [21]

Answer:

The stronger conjugate base will be the weaker acid; i.e., the acid with the smaller Ka-value.

Explanation:

Given conjugate base CN⁻ => weak acid => HCN =>  Ka =4.9 x 10⁻¹⁰

Given conjugate base OCN⁻ => weak acid=> HOCN => Ka = 3.5 x 10⁻⁴

Ka(HCN) << Ka(HOCN) => CN⁻ is a much stronger conjugate base than OCN⁻

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