95 percent of species known are invertebrates
Answer:
167,3 grams of O2 (g)
Explanation:
According to the following balanced equation:
C3H8 + 5 02 ---> 3 CO2 + 4 H20
We calculate the mass of the moles:
5 mol O2 = 16grams/mol x2x 5= 160 grams/mol
1 mol C3H8= 3 x12 grams/mol + 8 x 1 gram/mol= 44 grams/mol
If 44 grams C3H8 react with--------- 160 grams O2
46 gramsC3H8 react with --------X = (46x160)/44 =167, 3 grams O2
Answer:
0.20 moles
Explanation:
The pressure is proportional to the quantity of gas at a given temperature and volume. So, the quantity needs to be increased by a factor of ...
(35 psi)/(29.2 psi) = 175/146 ≈ 1.19863
The fractional increase required is ...
1.19863 -1 = 0.19863
__
The quantity of air currently in the tire is ...
1 mol·519.67°R/(atm·23.6442 L) × (29.2/14.7 atm) × (11.6 L) / (45+459.67)°R
= 1.0035 mol
so we need to add ...
(fraction to add) × (current quantity) = amount to add
0.19863 × 1.0035 mol = 0.1993 mol = amount to add
About 0.20 moles of air must be added to the tire to bring the pressure up.
Answer:
0.7246 M
Explanation:
Considering:
Or,
Given :
For 
:
Molarity = 2.086 M
Volume = 188.9 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 188.9×10⁻³ L
Thus, moles of :
Moles of = 0.39405 moles
For NaOH :
Molarity = 0.4607 M
Volume = 269.3 mL
The conversion of mL to L is shown below:
1 mL = 10⁻³ L
Thus, volume = 269.3×10⁻³ L
Thus, moles of NaOH :
Moles of NaOH = 0.1241 moles
According to the given reaction:
1 moles of react with 2 moles of NaOH to form 1 mole of sodium sulfate.
Thus,
2 moles of NaOH react with 1 mole of
1 mole of NaOH react with 1/2 mole of
0.1241 moles of NaOH react with (1/2)×0.1241 mole of
Moles of that got reacted = 0.06205 moles
Unreacted moles = Total moles - Moles that got reacted = 0.39405 - 0.06205 moles = 0.332 moles
Total volume = 188.9×10⁻³ L + 269.3×10⁻³ L = 458.2×10⁻³ L
Concentration of :
<u>Concentration of = 0.7246 M</u>
