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lawyer [7]
3 years ago
10

Need help, I am really confused??/

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
6 0
T=0.33c+32
0.33c=0.33×c: cost of the additional cards
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A publishing company has just published a new college textbook. Before the company decides the price at which to sell this textb
Kobotan [32]

Answer:b

Step-by-step explanation:

8 0
4 years ago
WILL MARK BRANLIEST PLEASE HELP -COOKIE
12345 [234]
This is simple:
divide 15 by 5 = 3     then divide .6 by 5 = 0.12

Add them together: 3.12 is your answer.
7 0
3 years ago
In a plane, line e is perpendicular to line f, line f is perpendicular to line g, and line h is parallel to line f. which of the
Over [174]

Answer:

a). line h is perpendicular to line g

Step-by-step explanation:

In these cases, always make a litle scetch, and just plot what is given.

You can immediately see the answer, which is answer a).

lf h is parallel to f and line f is perpendicular to line g,

then line h is perpendicular to line g.

8 0
4 years ago
Help me please it is math
777dan777 [17]
The formula for volume of a cylinder is : V = PI x r^2 x H

for both questions, plug in the known information and solve for the unknown:

Q1)  V = 450, H = 8
  so 450 = 3.14 x r^2 x 8
        450 = r^2 x 25.12
 r^2 = 450 / 25.12 = 17.914
r = sqrt(17.914) = 4.23  rounded to nearest tenth = 4.2 inches

Q2) V = 500, r=6
  
 500 = 3.14 x 6^2 x H
500 = 3.14 x 36 x h
500 = 113.04 x h

h = 500 / 113.047 = 4.42 = 4.4 inches

6 0
3 years ago
(1 point) For the equation given below, evaluate ′ at the point (−1,2). (5−)^4+4^3=2433. ′ at (−1,2) =
ryzh [129]

Answer:

\dfrac{343}{71}

Step-by-step explanation:

Given the equation

(5x-y)^4+4y^3=2433

Find the derivative:

((5x-y)^4+4y^3)'=(2433)'\\ \\4(5x-y)^3\cdot (5x-y)'+4\cdot 3y^2\cdot y'=0\\ \\4(5x-y)^3\cdot (5-y')+12y^2y'=0

Substitute

x=-1\\ \\y=2,

then

4(5\cdot (-1)-2)^3\cdot (5-y')+12\cdot 2^2\cdot y'=0\\ \\4(-5-2)^3(5-y')+48y'=0\\ \\4\cdot (-7)^3\cdot (5-y')+48y'=0\\ \\-1,372(5-y')+48y'=0\\ \\-6,860+1,372y'+48y'=0\\ \\1,420y'=6,860\\ \\y'=\dfrac{6,860}{1,420}=\dfrac{686}{142}=\dfrac{343}{71}

6 0
3 years ago
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