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Eddi Din [679]
3 years ago
8

Given the geometric sequence where a1 = 3 and r = √2 find a9

Mathematics
1 answer:
Zigmanuir [339]3 years ago
8 0

Answer:

a_9=48

Step-by-step explanation:

we are given

sequence is geometric

so, we can use nth term formula

a_n=a_1(r)^{n-1}

we have

a_1=3

r=\sqrt{2}

we have to find a9

so, we can plug n=9

we get

a_9=3(\sqrt{2})^{9-1}

a_9=2^4\cdot \:3

a_9=48

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Is there any more to this question? Because-5 doesn’t belong anywhere
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3 years ago
Jem boy wants to make his 8-meter square pool into a rectangular one by increasing its length by 2m and decreasing its width by
butalik [34]
Side = 8m
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 here we will use the special product (x+y) (x-y)
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3 0
3 years ago
How does the graph of this function compare with the graph of the parent function, y=1/x? It is shifted right 5 units and up 2 u
nasty-shy [4]

Answer:

It is shifted left 5 units and up 2 units from the parent function.

Step-by-step explanation:

Given

y = \frac{1}{x}

y' = \frac{1}{x+5} + 2

Required

Compare both functions

First, translate y, 5 units left.

The rule is:

(x,y) \to (x + 5,y)

So, we have:

y = \frac{1}{x}

y_1 = \frac{1}{x + 5}

Next, translate y1, 2 units up.

The rule is:

(x,y) \to (x,y+2)

So, we have:

y' = y_1 + 2

y' = \frac{1}{x + 5} + 2

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5 units left and 2 units up

7 0
3 years ago
Answer correctly for brainliest and also a thanks ! Don't answer if you don't know it please !
Drupady [299]
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You can do this by using the eqn

y=0.5x-1.3
y=0.5(15)-1.3
y = 7.5-1.3
y = 6.2

y=0.5(16)-1.3
y=8-1.3
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5 0
3 years ago
Please I Really Need Help.The coordinate plane below represents a city. Points A through F are schools in the city.
almond37 [142]

Answer:

Part A) The system of inequalities is

x\geq2  and  y\geq2

Part B) In the procedure

Part C) The schools that Natalie is allowed to attend are A,B and D

Step-by-step explanation:

Part A: Using the graph above, create a system of inequalities that only contain points C and F in the overlapping shaded regions

we have

Points C(2,2), F(3,4)

The system of inequalities could be

x\geq2 -----> inequality A

The solution of the inequality A is the shaded area at the right of the solid line x=2

y\geq2 -----> inequality B

The solution of the inequality B is the shaded area above of the solid line y=2

see the attached figure N 1

Part B: Explain how to verify that the points C and F are solutions to the system of inequalities created in Part A

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities

<em>Verify point C</em>

C(2,2)    

<em>Inequality A</em>

x\geq2 -----> 2\geq2 ----> is true

<em>Inequality B</em>

y\geq2 ------> 2\geq2 ----> is true

therefore

Point C is a solution of the system of inequalities

<em>Verify point D</em>

F(3,4)    

<em>Inequality A</em>

x\geq2 -----> 3\geq2 ----> is true

<em>Inequality B</em>

y\geq2 ------> 4\geq2 ----> is true

therefore

Point D is a solution of the system of inequalities

Part C: Natalie can only attend a school in her designated zone. Natalie's zone is defined by y < −2x + 2. Explain how you can identify the schools that Natalie is allowed to attend.

we have

y < -2x+2

The solution of the inequality is the shaded area below the dotted line y=-2x+2

The y-intercept of the dotted line is the point (0,2)

The x-intercept of the dotted line is the point (1,0)

To graph the inequality, plot the intercepts and shade the area below the dotted line

see the attached figure N 2

therefore

The schools that Natalie is allowed to attend are A,B and D

3 0
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