Ask question

Ask question

All categories

3 years ago

12

A 500N person stands 2.5m from a wall against which a horizontal beam is attached. The beam is 6m long and weighs 200N. A cable

is attached to the free end of the beam and makes an angle of 45 to the horizontal and is attached to the wall.
1)Determine the magnitude of the tension of the cable.
2)Determine the reaction force that the wall exerts on the beam.

1 answer:

Vinil7 [7]3 years ago

5 0

PART A)

Here by force balance along Y direction

$Tsin45 + F_y = 500 + 200$

Force balance along X direction

$Tcos45 = F_x$

now by torque balance

$Tsin45 (6) = 500 (2.5) + 200 (3)$

$T(4.24) = 1250 + 600$

$T = 436.3 N$

PART B)

now from above equations

$Tsin45 + F_y = 700$

$F_y = 391.5 N$

$F_x = Tcos45 = 308.5 N$

now net reaction force of wall is given as

$F = \sqrt{F_x^2 + F_y^2}$

$F = 498.4 N$

You might be interested in

Five basket ball teams are playing in a tournament. The teams will play with each other only one time. How many games will be pl

77julia77 [94]

<em>Ten games</em> will be played.

The first team can be any one of 5 . For each of those, the opponent can be any one of the other 4 .

Number of ways to pair them up = (5 x 4) = 20 ways .

<em>BUT</em> ... Whether the Reds play the Blues, or the Blues play the Reds, it's the SAME GAME. Each possible game shows up twice in the list of 20 ways. So there are really only 10 different pairs ==> <em>10 games</em> .

3 0

3 years ago

A type of bacteria lives in the roots of plants. The bacteria helps the plants obtain nutrients. The roots are a moist home, whi

rodikova [14]

Answer:

Rhizobium.

Explanation:

The roots of most of these plants have nitrogen-fixing bacteria known as rhizobium. It helps to change nitrogen which is present in the air into the nitrates which are plants, and that is need to synthesize proteins.

Rhizobium bacteria occupy the root hairs which are present on the plants, they help the plant to grow and keep up with other plants. When the one plant dies, the fixed nitrogen which is present in it will release, and making it available for other plants, and this process helps to fertilize the soil in the environment.

6 0

3 years ago

During a solar eclipse, the Moon, Earth, and Sun all lie on the same line, with the Moon between the Earth and the Sun.

lord [1]

Answer:

(a) $F_{sm} = 4.327\times 10^{20}\ N$

(b) $F_{em} = 1.983\times 10^{20}\ N$

(c) $F_{se} = 3.521\times 10^{20}\ N$

Solution:

As per the question:

Mass of Earth, $M_{e} = 5.972\times 10^{24}\ kg$

Mass of Moon, $M_{m} = 7.34\times 10^{22}\ kg$

Mass of Sun, $M_{s} = 1.989\times 10^{30}\ kg$

Distance between the earth and the moon, $R_{em} = 3.84\times 10^{8}\ m$

Distance between the earth and the sun, $R_{es} = 1.5\times 10^{11}\ m$

Distance between the sun and the moon, $R_{sm} = 1.5\times 10^{11}\ m$

Now,

We know that the gravitational force between two bodies of mass m and m' separated by a distance 'r' is given y:

$F_{G} = \frac{Gmm'_{2}}{r^{2}}$ (1)

Now,

(a) The force exerted by the Sun on the Moon is given by eqn (1):

$F_{sm} = \frac{GM_{s}M_{m}}{R_{sm}^{2}}$

$F_{sm} = \frac{6.67\times 10^{- 11}\times 1.989\times 10^{30}\times 7.34\times 10^{22}}{(1.5\times 10^{11})^{2}}$

$F_{sm} = 4.327\times 10^{20}\ N$

(b) The force exerted by the Earth on the Moon is given by eqn (1):

$F_{em} = \frac{GM_{s}M_{m}}{R_{em}^{2}}$

$F_{em} = \frac{6.67\times 10^{- 11}\times 5.972\times 10^{24}\times 7.34\times 10^{22}}{(3.84\times 10^{8})^{2}}$

$F_{em} = 1.983\times 10^{20}\ N$

(c) The force exerted by the Sun on the Earth is given by eqn (1):

$F_{se} = \frac{GM_{s}M_{m}}{R_{es}^{2}}$

$F_{se} = \frac{6.67\times 10^{- 11}\times 1.989\times 10^{30}\times 5.972\times 10^{24}}{((1.5\times 10^{11}))^{2}}$

$F_{se} = 3.521\times 10^{20}\ N$

7 0

3 years ago

Um automóvel percorre 6,0 km para o norte e, em seguida 8,0 km para o leste. A intensidade do vetor posição, em relação ao ponto

Valentin [98]

Answer:

Explanation:

A car travels 6.0 km to the north and then 8.0 km to the east. The intensity of the position vector, in relation to the starting point is: a) 14 km b) 2.0 km c) 12 km d) 10 km e) 8.0 km

Check attachment for diagram

The intensity of the position vector is equal to the displacement,

So, to calculate the displacement, we need to find the length of the straight line from starting point to end point.

So, applying Pythagorean theorem

c² = a² + b²

R² = 6² + 36²

R² = 36 + 64

R² = 100

R = √100

R = 10 km.

Verifique el adjunto para ver el diagrama

La intensidad del vector de posición es igual al desplazamiento,

Entonces, para calcular el desplazamiento, necesitamos encontrar la longitud de la línea recta desde el punto inicial hasta el punto final.

Entonces, aplicando el teorema de Pitágoras

c² = a² + b²

R² = 6² + 36²

R² = 36 + 64

R² = 100

R = √100

R = 10 km.

7 0

3 years ago

As the pulses interfere destructively there is a point in time when the string is perfectly straight. Which of the following sta

uysha [10]

According to the statement we can deduce that the resulting amplitude of the wave pulse is zero when there is a destructive interference of two pulses and the chain is straight. At this point the potential energy will be zero, therefore when applying the energy conservation theorem, the potential energy must be equal to the kinetic energy and be conserved. The potential energy will be totally transferred as kinetic energy and therefore that will be the only energy present in the string.

Thus, the option C is correct.

3 0

3 years ago