Answer:
The lens to be used for the objective is lens A
Explanation:
The objective of a compound microscope
The focal length of the lens used for the objective = 1/(magnification obtained)
The focal length of most modern is equal to the tube length
The range of sizes for the focal length of a microscope is between 2 mm and 40 mm
Therefore, the appropriate lens to be used for the objective of the compound is lens A that has a focal length of 0.50 cm = 5 mm
The two units for measuring the diameter of nucleus atom are femtometre and metre.
How do you measure the size of the nucleus ?
Nucleus size is expressed in fermi, often known as femtometers. between a lighter and a heavier nucleus. Despite its modest size, the nucleus contains the majority of an atom's mass. The weight or mass of the atom's nucleus and neutrons are determined by neutrons.
femtometre (fm), which equals
metre.
A nucleus' diameter largely depends as to how many particles it contains, from about 4 fm for a light nucleus like carbon to 15 fm for a heavy nucleus as lead.
Learn more about nucleus of an atom here :-
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Answer:
Explanation:
Let mass of bullet = m1 = 28g= 0.028 kg
mass of pendulum = m2 = 3.1 kg
Quartz, gold and calcite are examples of minerals, coal is a fossil fuel
Answer:
planet that is farthest away is planet X
kepler's third law
Explanation:
For this exercise we can use Kepler's third law which is an application of Newton's second law to the case of the orbits of the planets
T² = (
a³ = K_s a³
Let's apply this equation to our case
a =
for this particular exercise it is not necessary to reduce the period to seconds
Plant W
10² = K_s
a_w =
a_w =
4.64
Planet X
a_x =
a_x = \frac{1}{ \sqrt[3]{K_s} } 74.3
Planet Y
a_y =
a_y = \frac{1}{ \sqrt[3]{K_s} } 18.6
Planet z
a_z =
a_z = \frac{1}{ \sqrt[3]{K_s} } 41.8
From the previous results we see that planet that is farthest away is planet X
where we have used kepler's third law