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3 years ago

How long does creatine phosphate provide every

1 answer:

6 0

Creatine phosphate can supply the energy needs of a working muscle at a very high rate, but only for about 8–10 seconds.

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An astronaut drops a rock on the surface of an asteroid.The rock is released from rest at a height of 0.86 m above the ground, a

SCORPION-xisa [38]

Answer:

$a_y=0.92m/s^2$

Explanation:

To solve this problem we use the formula for accelerated motion:

$y=y_0+v_{y0}t+\frac{a_yt^2}{2}$

We will take the initial position as our reference ( $y_0=0m$ ) and the downward direction as positive. Since the rock departs from rest we have:

$y=\frac{a_yt^2}{2}$

Which means our acceleration would be:

$a_y=\frac{2y}{t^2}$

Using our values:

$a_y=\frac{2(0.86m)}{(1.37s)^2}=0.92m/s^2$

5 0

4 years ago

If the work function of a material is such that red light of wavelength 700 nm just barely initiates the photoelectric effect, w

marishachu [46]

Answer:

2.13 x 10^-19 J or 0.53 eV

Explanation:

cut off wavelength, λo = 700 nm = 700 x 10^-9 m

λ = 400 nm = 400 x 10^-9 m

Use the energy equation

$E = \frac{h c}{\lambda _{o}}+K$

Where, K be the work function

$\frac{h c}{\lambda} = \frac{h c}{\lambda _{o}}+K$

$K =hc\left ( \frac{1}{\lambda } -\frac{1}{\lambda _{0}}\right )$

$K =6.63\times 10^{-34}\times 3\times 10^{8}\left ( \frac{1}{4\times 10^{-7} } -\frac{1}{7\times 10^{-7}}\right )$

K = 2.13 x 10^-19 J

K = 0.53 eV

3 0

3 years ago

PLEASE HELP ASAP! WILL GIVE BRAINLIEST TO CORRECT ANSWER! HELP!! HELP!!

Phoenix [80]

Answer:

1. cell membrane

2. golgi body

3. mitochondrion

4. cytoplasm

5. nucleolus

6. nucleus

Explanation:

4 0

3 years ago

Read 2 more answers

When light reflects on a mirror, does it undergo a phase change?

Lynna [10]

The light does not undergo a phase change.

Also, the surface of a mirror is a rigid boundary.

5 0

3 years ago

A block with a weight of 3.0 N is at rest on a horizontal surface.A 1.0 N upward force is applied to the block by means of an at

Genrish500 [490]

Answer:

Explanation:

Given

weight of block $W=3\ N$

A force is of $F=1 N$ is applied on the block

As 1 N is less than weight of block so block exert Force less than its weight

$F_{net}=mg-F$

$F_{net}=3-1=2\ N$

So Block exert a force of 2 N downward on floor

8 0

4 years ago