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katrin [286]
3 years ago
10

A 3​-card hand is dealt from a standard​ 52-card deck, and then one of the 3 cards is chosen at random. If only one of the cards

in the hand is a 3​, what is the probability that the chosen card is a 3​?
The probability that the chosen card is a 3 is?
​(Simplify your answer. Type an integer or a​ fraction.)
Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
7 0

Answer:

1/3

Step-by-step explanation:

Once you know there is a 3 in the hand, and only one card is drawn from the cards in the hand, then the probability of drawing the 3 is 1/3.

s2008m [1.1K]3 years ago
3 0

<u>Answer:</u>

P (chosen card is 3) = \frac{1}{3}

<u>Step-by-step explanation:</u>

We are given that a 3​-card hand is dealt from a standard​ 52-card deck, and then one of the 3 cards is chosen at random.

Given that only one of the cards is a 3, we are to find the probability that the chosen card is a 3.

Since only one card is a 3 and one card is chosen so:

P (chosen card is 3) = 1 / 3

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user100 [1]

Answer:

Keisha bought 3 sandwiches and 5 lemonades.

Equations:  x + y = 8       2x + y = 11

Step-by-step explanation:

To solve a problem with two variables, you need to set up a system of equations comparing the two variables and solve using either substitution or elimination.  If 'x' represents the number of sandwiches and 'y' represents the number of lemonades, then x + y = 8 because they bought a total of 8 items.  Also, the cost of each item is given as well as the total amount of money spent.  So, our second equation is: 2x + y = 11.   We can use inverse operations to solve for 'y' in the first equation:  x + y - x = 8 - x which simplifies to: y = 8 - x.  We can then use this expression to substitute in for the variable 'y' in the second equation:  2x + 8 - x = 11.

Combine like terms:  x + 8 = 11

Inverse Operations: x +8 - 8 = 11 - 8

Solve:  x = 3, so Keisha bought 3 sandwiches

Solve for y:  y = 8 - 3 = 5, so Keisha bought 5 lemonades

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