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2 years ago

11

Sam plans to walk his dog a distance of a mileHe walks 3/8 of a mile and stop and get a bottle of waterThen he walks 1/8 of a mi

le and stop to talk to a friendHow far does Sam still have to walk his dog

1 answer:

DedPeter [7]2 years ago

3 0

Answer:

1/2 mile

Step-by-step explanation:

3/8+1/8=4/8 or 1/2 simplified

1-1/2=1/2

same has to walk 1/2 mile more to walk his dog a full mile

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Solve the equation x^2-4x+85=0

lara [203]

Can't factor
use quadratic
for
ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^2-4ac} }{2a}$

given
1x^2-4x+85=0
a=1
b=-4
c=85

x= $\frac{-(-4)+/- \sqrt{(-4)^2-4(1)(85)} }{2(1)}$
x= $\frac{4+/- \sqrt{16-340} }{2}$
x= $\frac{4+/- \sqrt{-324} }{2}$
x= $\frac{4+/- (\sqrt{-1})(\sqrt{324}) }{2}$
remember that √-1=i
x= $\frac{4+/- i(\sqrt{324}) }{2}$
x= $\frac{4+/- i(18) }{2}$
x=2+/-9i

x=2+9i or x=2-9i

3 0

3 years ago

Answer this please please

zloy xaker [14]

Answer:

x is less than -3

Step-by-step explanation:

3x^2+9x<0

x^2+3x<0

x(x+3)<0

x+3<0

x<-3

6 0

2 years ago

A monkey is swinging from a tree. On each swing, she travels along an arc that is 75% as long as the previous swing's arc. The t

mr_godi [17]

Answer:

Total length of the first swing=64 m

Step-by-step explanation:

The total length of all four swings can be expressed as;

Total length of all 4 swings=Length of first swing+length of second swing+length of third swing+length of fourth swing

where;

Total length of all 4 swings=175 m

Length of first swing=x

Length of second swing=75% of length of first swing=(75/100)×x=0.75 x

Length of third swing=75% of length of second swing

Length of third swing=(75/100)×0.75 x=0.5625 x

Length of fourth swing=75% of length of third swing

Length of fourth swing=(75/100)×0.5625 x=0.421875 x

replacing;

Total length of all 4 swings

175=x+0.75 x+0.5625 x+0.421875 x

2.734375 x=175

x=175/2.734375

x=64

Total length of the first swing=x=64 m

3 0

3 years ago

Read 2 more answers

The answer to question 24 please!

erica [24]

Answer:

9

Step-by-step explanation:

5 0

2 years ago

ank A contains 80 gallons of water in which 20 pounds of salt has been dissolved. Tank B contains30 gallons of water in which 5

adell [148]

Answer:

$\frac{dx}{dt}=2-\frac{3}{40}x+\frac{y}{15}$

$\frac{dy}{dt}=\frac{3}{40}x-\frac{y}{5}$

x(0)=20,y(0)=5

Step-by-step explanation:

We are given that

Tank A contains water=80 gallons

x(0)=20,y(0)=5

Tank B contains water=30 gallons

Rate=4 gallon/min

Concentration of salt is pumped into tank=0.5 pound /gallon of water

Solution pumped from tank A to tank B at the rate=6 gallons/min

Solution pumped from tank B to tank A at the rate=2gallon/min

Solution from tank B is pumped out of the system at the rate=4 gallon/min

We have to find the DE at time t

For x

Rate in= $0.5\times 4+y(t)/30\times 2$

Rate in= $2+y/15$

Rate out= $x/80\times 6$

Rate out=3x/40[/tex]

$\frac{dx}{dt}=$ Rate in-Rate out

$\frac{dx}{dt}=2+y/15-3x/40$

$\frac{dx}{dt}=2-\frac{3}{40}x+\frac{y}{15}$

For y

Rate in= $x/80\times 6$

Rate in=3/40x

Rate out= $y/30\times (4+2)$

Rate out=y/5

$\frac{dy}{dt}=$ Rate in-Rate out

$\frac{dy}{dt}=\frac{3}{40}x-\frac{y}{5}$

8 0

2 years ago