The first thing to do is to convert the mass of sodium
sulfate to moles. Since the given is in milligrams convert it to grams which
would be 0.02824 grams. The number of moles can be calculated by dividing the
converted weight with the given molar mass which is 139.04 g/mol. The number of
mols in the solution is 2.03x10^-4 mols. Then divide the number of moles with
0.02355 L. The molarity of the solution is 0.00862 M.
Answer:
The equation is already balanced. There's an equal number of materials on each side of the equation.
Answer:
C₂H₃Cl₃O₂
Explanation:
Given parameters:
Percentage composition:
14.52% C
1.83% H
64.30% Cl
19.35% O
Molar mass = 165.4 g/mo
Unknown:
Empirical formula = ?
Solution:
The empirical formula of a compound is the simplest formula of a compound. To solve this problem, let us follow the process below:
C H Cl O
%composition 14.52 1.83 64.3 19.35
Molar mass 12 1 17 16
number of
moles 14.52/12 1.83/1 64.3/3.5 19.35/16
1.21 1.83 1.81 1.21
Divide by
the smallest 1.21/1.21 1.83/1.21 1.81/1.21 1.21/1.21
1 1.51 1.51 1
multiply
by 2 2 3 3 2
Empirical formula C₂H₃Cl₃O₂
Answer:
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