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Mazyrski [523]
3 years ago
10

I need some help for two math questions.. [These are meant to solve for x btw]

Mathematics
1 answer:
Vaselesa [24]3 years ago
7 0

Answer:

x=S+bc/b+c

 x=S−2ab/2(a+b)

Step-by-step explanation:

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

x=S+bcb+c

Isolate the variable by dividing each side by factors that don't contain the variable.

x=S−2ab2(a+b)

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I have problems to found my answer, somebody can help me?
Thepotemich [5.8K]
So final step to do is you square root the x^2 and square root the 4000 which will get you answer of x = 63.2455532034 which can be 63.2. Hope this help!!
8 0
3 years ago
PLEASE HELP ME ASAP..........
Effectus [21]
7.079- the first option
3 0
3 years ago
Read 2 more answers
Does anyone understand how to solve this?
Nataliya [291]

a f(a) is the function f(x) where x is replaced by a.

So we have

(3x^2 + x + 3 - (3a^2 + a + 3)) / ( x - a)

= (3x^2 - 3a^2 + x - a) / (x = a) Answer

b (3(x + h)^2 + x + h + 3 - (3x^2 + x + 3)) / h

= (3x^2 + 6xh + 3h^2 + x + h - 3x^2 - x - 3) ) / h

= (6xh + h + 3 h^2) / h

= 6x + 3h + 1 Answer



6 0
3 years ago
If C = 2m2 + m and D = 2 – 6m + 2m², find an expression that equals<br> 2C - 2D in standard form.
lidiya [134]
C = 2m^2 + m
D = 2 - 6m + 2m^2

2C = 2(2m^2 + m) = 4m^2+2m
2D = 2(2-6m+2m^2) = 4-12m+4m^2

2C - 2D =
4m^2+2m-(4-12m+4m^2) =
4m^2+2m-4+12m-4m^2 =
0m^2 + 14m -4 =
14m - 4
3 0
3 years ago
What is 6/25-63/125<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B16%7D%7B25%7D%20%20-%20%5Cfrac%7B63%7D%7B125%7D%20" id="Te
juin [17]

6/25-63/125


Make the denominator the same:

= 30/125 - 63/125


Subtract:

= -33/125


Answer: -33/125

6 0
3 years ago
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