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Mazyrski [523]
4 years ago
10

I need some help for two math questions.. [These are meant to solve for x btw]

Mathematics
1 answer:
Vaselesa [24]4 years ago
7 0

Answer:

x=S+bc/b+c

 x=S−2ab/2(a+b)

Step-by-step explanation:

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

x=S+bcb+c

Isolate the variable by dividing each side by factors that don't contain the variable.

x=S−2ab2(a+b)

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7 0
3 years ago
Please help asap please
vodka [1.7K]
Ok, so lets evaluate this here:
2/3 (x - 6) - y       Let's do the first part: 2/3 (x - 6)
                           If X = 9 then we subtract 6 from 9 and get 3. Then we multiply 
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Then lets do the 2nd part: 2 - y.
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3 years ago
which of the following is the conjugate of a complex numbcber with -4 as the real part and 2 as the imaginary part( 6 points
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I don’t know sorry mmm ok
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