<span>W′(6, −6), K′(8, −6), L′(9, −5) , and X′(5, −5) </span>
Answer:
The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.
Step-by-step explanation:
Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.
But,
<P = 048°
<Q =
- 
= 0
Sum of angles in a triangle = 
<P + <Q + <S = 
048° + 0
+ <S = 
+ <S = 
<S =
- 
= 
<S = 
Applying the Sine rule,
=
= 
= 
= 
= 
⇒ y = 
= 12.703
y = 12.70 km
= 
= 
= 
⇒ x = 
= 10.0475
x = 10.05 km
Thus,
the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.
Answer:
A) 25
Step-by-step explanation:
You use x= -b/2a in order to get your maximum so x= -10/ 2(-5) and you get x=1. You plug 1 into the function as h(1)=-5(1)^2 + 10(1)+ 20 which gets you 25
Answer:
$1200 interest
Step-by-step explanation:
$30,000 divided by 100 = 300 , 300 multipled by 4 = 1200 , thats how to find what 4% would be
The length of the edge would be 5cm