1) 3<em>x</em>
2) 3<em>(x)</em>
3) 3·<em>x</em>
4) 3*<em>x</em>
Answer:
4^(-11)
Step-by-step explanation:
To divide powers, subtract the exponents.
4^(-2) / 4^9
-2-9=-11
So, the answer is 4^(-11), which is basically 4 to the eleventh power.
4x10 6th power = 280
1x10 4th power =13
So if I'm right 4x10 6power is greater
Let x represent milk chocolate bar
y represent creamy nougat bars
3x+4y=4.25
6x+4y=6.5
6x+4y=6.5
-
3x+4y=4.25
=
3x=2.25
x=$0.75
y=$0.5. As a result, one milk chocolate bar costs $0.75 and one creamy nougat bar costs $0.5. Hope it help!
Answer:
<h2>Cubing both sides of an equation is reversible.</h2>
Step-by-step explanation:
Squaring both sides of an equation is irreversible, because the square power of negative number gives a positive result, but you can't have a negative base with a positive number, given that the square root of a negative number doesn't exist for real numbers.
In case of cubic powers, this action is reversible, because the cubic root of a negative number is also a negative number. For example
![\sqrt[3]{x} =-1](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%20%3D-1)
We cube both sides
![(\sqrt[3]{x} )^{3} =(-1)^{3} \\x=-1](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7Bx%7D%20%29%5E%7B3%7D%20%3D%28-1%29%5E%7B3%7D%20%5C%5Cx%3D-1)
If we want to reverse the equation to the beginning, we can do it, using a cubic root on each side
![\sqrt[3]{x}=\sqrt[3]{-1} \\\sqrt[3]{x}=-1](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%3D%5Csqrt%5B3%5D%7B-1%7D%20%5C%5C%5Csqrt%5B3%5D%7Bx%7D%3D-1)
There you have it, cubing both sides of an equation is reversible.