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MissTica
3 years ago
12

PLS HELP !!! a. 15 b. 1 c. 2 d. 11

Mathematics
2 answers:
Serjik [45]3 years ago
5 0

Answer:

d

Step-by-step explanation:

ive had this exac problem before

lozanna [386]3 years ago
4 0

Answer:

B. 1

Step-by-step explanation:

Since the sides are equal to each other, the equations will be equal.

4x + 7 = x + 10

      -7          -7

---------------------

4x= x + 3

-x    -x

-------------

3x = 3

----   ---

3      3

x = 1

The answer is 1.

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3 years ago
The length of a rectangle is 2cm longer than the width. The perimeter is 52cm. What is the length and width of the rectangle?
Liula [17]

Answer:

Width = 12 cm

Length = 14 cm

Step-by-step explanation:

Rectangle:

Let the width  = x cm

So, the length = (x+2) cm

Perimeter  = 52 cm

2 *(l+b) = 52

2 *(x+2  + x) =  52

   2 * ( 2x + 2) = 52

           2x + 2  = 52/ 2

           2x + 2  = 26

                 2x = 26- 2

                  2x = 24

                    x = 24/2

                    x = 12

Width = 12 cm

Length = 14 cm

3 0
3 years ago
What Ps the value<br>of (100)^o​
Bond [772]

Answer:

(100)^0=1

Step-by-step explanation:

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6 0
3 years ago
(a) The perimeter of a rectangular field is 310 m.
Softa [21]

Answer:

<h3 />

a. \boxed{ \bold{ \boxed{ \sf{width \: of \: rectangular \: field \:  = 71 \: meter}}}}

b. \boxed{ \bold{ \boxed{ \sf{length \: of \: rectangular \: painting \:  = 85 \: cm}}}}

Step-by-step explanation:

a. Given,

Perimeter of rectangular field ( P ) = 310 m

Length of the field ( L ) = 84 m

Width of the field ( W ) = ?

<u>Finding </u><u>the </u><u>width </u><u>of </u><u>the </u><u>rectangular</u><u> </u><u>field</u>

\boxed{ \sf{perimeter \: of \: rectangle = 2(l + w)}}

plug the values

⇒\sf{310 = 2(84 + w)}

Distribute 2 through the parentheses

⇒\sf{310 = 168 + 2w}

Swap the sides of the equation

⇒\sf{168 + 2w = 310}

Move 168 to right hand side and change it's sign

⇒\sf{2w = 310 - 168}

Subtract 168 from 310

⇒\sf{2w = 142}

Divide both sides of the equation by 2

⇒\sf{ \frac{2w}{2}  =  \frac{142}{2} }

Calculate

⇒\sf{w = 71 \: m}

Width = 71 meters

------------------------------------------------------------

2. Given,

Area of rectangular painting ( A ) = 5185 cm²

Width of the painting ( w ) = 61 cm

Length of the painting ( l ) = ?

<u>Finding </u><u>length </u><u>of </u><u>the </u><u>painting</u>

\boxed{ \sf{area \: of \: rectangle = l \times w}}

plug the values

⇒\sf{5185 = 61l}

Swap the sides of the equation

⇒\sf{61 \: l \:  = 5185}

Divide both sides of the equation by 61

⇒\sf{ \frac{61 \: l}{61}  =  \frac{5185}{61} }

Calculate

⇒\sf{l = 85} cm

Length = 85 cm

Hope I helped!

Best regards !!!

4 0
3 years ago
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