Answer:
(1) 102.55 in
(2) 316.69 in²
Step-by-step explanation:
Applying (1)
a² = b²+c².............. Equation 1
Given: a = 25 in, b = 20 in,
25² = 20²+b²
b² = 25²-20²
b² = 225
b = √225
b = 15 in
b = diameter of the semicircle
The lenght of the semicircle = πd/2 = 3.14×15/2 = 23.55 in
Therefore,
P = 37+25+17+23.55 = 102.55 in
(2) Applying,
A = Area of the tripezium- area of the semi circle
A = [h(a+b)/2]-πh²/8.............. Equation 2
Given; h = 15 in, a = 17 in, b = 37 in
A = (15(17+37)/2)-(3.14×15²/8)
A = 405-88.31
A = 316.69 in²
