I need help with all except graph on first question please! Work shown or not doesn’t matter

Mathematics

1 answer:

Jobisdone [24]3 years ago

5 0

Answer:

y = 7/5x + 18/5

Step-by-step explanation:

so we have y = mx + b

f(1) = 5

f(-4) = -2

so let's find b

so like if you do (5 - (-2))/(1 - (-4)) you get (5 + 2)/(1 + 4) = 7/5

y = 7/5x + b

so now we can plug in a value like f(1) = 5

5 = (7/5)1 + b

b = 18/5

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Write the slope intercept form of a line going through

anyanavicka [17]

Perpendicular = opposite sign and reciprocal slope
Slope 2 turns into -1/2
Y = -1/2x + b
Plug in the point
-5 = -1/2(2) + b, b = -4
Solution: y = -1/2x - 4

5 0

3 years ago

A. f(x) = l-2xl - 3 Domain: {1, 2, 3} Find the range

gizmo_the_mogwai [7]

Hello there!

We are given the function:

$\displaystyle \large{ f(x) = | - 2x| - 3} \\$

To find the range, we know that domain is the set of all x-values and also called 'input' while range is the set of all y-values and also called 'output'.

Basic Function - you add the input, you get the output. You add x-value in a function, you get y-value. You add domain, you get range.

So, we substitute x = 1,2 and 3 in the function.

x = 1

$\displaystyle \large{ f(1) = | - 2(1)| - 3} \\ \displaystyle \large{ f(1) = | - 2| - 3} \\$

Recall that any numbers in absolute value are always positive.

$\displaystyle \large{ f(1) = 2 - 3} \\ \displaystyle \large{ f(1) = - 1} \\$

x = 2

$\displaystyle \large{ f(2) = | - 2(2)| - 3} \\ \displaystyle \large{ f(2) = | - 4 | - 3} \\ \displaystyle \large{ f(2) = 4 - 3} \\ \displaystyle \large{ f(2) = 1}$

x = 3

$\displaystyle \large{ f(3) = | - 2(3)| - 3} \\ \displaystyle \large{ f(3) = | - 6| - 3} \\ \displaystyle \large{ f(3) = 6 - 3} \\ \displaystyle \large{ f(3) = 3}$