1/3+2/9=1/6x-4/6
3/9+2/9=1/6x-4/6
5/9=1/9x-4/6
5=x-6
x=11
a. In order for to be a PDF, needs to be non-negative (it is) and the integral over its support must evaluate to 1. is symmetric about , i.e. even, so
and so is indeed a PDF.
b. Let be a random variable with as its PDF. Then
The integrand is odd, so the integral vanishes and the mean is .
The variance of is
The second moment is
This integrand is even, so
Integrate by parts, taking
so that
Integrate by parts again, this time with
and so the variance is .
Answer:
x-8
Step-by-step explanation:
Answer:
it is c
Step-by-step explanation: